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sergij07 [2.7K]
3 years ago
11

If 74.5 m of oxygen are collected at a pressure of 98.0 kPa, what volume will the gas occupy if the

Chemistry
1 answer:
sergey [27]3 years ago
4 0

Answer:

80.8 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 74.5 mL

Initial pressure (P₁) = 98.0 kPa

Final pressure (P₂) = 90.4 kPa

Final volume (V₂) =?

The final volume of the gas can be by using the Boyle's laws equation as follow:

P₁V₁ = P₂V₂

98 × 74.5 = 90.4 × V₂

7301 = 90.4 × V₂

Divide both side by 90.4

V₂ = 7301 / 90.4

V₂ = 80.8 mL

Thus, the volume of the gas is 80.8 mL

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_NaHCO(s) --&gt; _CO2+_NaCO(s)+_H2O<br><br>balance the equation​
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The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

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Make an equation

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