I believe this question is missing an image. However, I will just tell how how to solve such question and you can apply this solution to the triangle you have.
In any given triangle, the sum of the measure of the three angles must be equal to 180 degrees.
Therefore, for a triangle pqr:
measure angle pqr + measure angle prq + measure angle rqp = 180 degrees
If you have one angle given, then the sum of the other two angles will be equal to 180 - measure of the given angle.
If you have two angles given, then the measure of the third angle will be equal to 180 - the sum of the other two angles.
Step-by-step explanation:
Initial velocity(u) = 60 km/hr = 50/3 m/s
final velocity(v)= 0 (stops at rest)
acceleration(a) = -0.05 m/s²
display (s)=?
v²-u²=2as
0²- (50/3)= 2(-0.05)s
2500/9= 0.1s
s= 25000/9 m
The answer should be 65. The number be added is doubled. +4,+8, +16, +32 So 32+33=65 65+64=129
Answer:
y = 18x + 10
slope = 18
y-intercept = 10
Step-by-step explanation:
The situation given in the problem is linear and can be represented using slope-intercept form of a linear equation: y = mx + b, where 'm' is equal to the slope, 'b' is equal to the y-intercept, 'x' is the number of hours and 'y' is the total number of miles.
Given that Jasmine has already biked 10 miles, her initial value, or y-intercept would be 10. Since she is now biking at a rate of 18 miles per hour, her rate of change, or slope, would be 18.
Using these values for 'm' and 'b': y = 18x + 10
P(B|A) (option B)
Doesn't affect (option A)
P(B|A) = P(B) (option A)
Explanation:
1) Conditional probabilities could be in the form P(A|B) or P(B|A)
P(B|A) is a notation that reads the probability of event B given that event A has occurred.
P(B|A) (option B)
2) Independent events do not affect the outcome of each other
For event A and B to be independent, the probability of event A occurring doesn't affect the the probability of event B occurring
Doesn't affect (option A)
3) Events A and B are independent if the following are satisfied:
P(A|B) = P(A)
P(B|A) = P(B)
The ones that appeared in the option is P(B|A) = P(B) (option A)