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Kamila [148]
3 years ago
12

Can somebody help me with this.​

Chemistry
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

HI

H₂O

H₃O⁺

I⁻

Explanation:

Bronsted-Lowry acids are chemicals that can donate protons, and Bronsted-Lowry bases are chemicals that can accept them. Conjugate bases and acids are the resulting effect of losing or gaining a proton in the form of H⁺.

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One gram of salt in 100 liters of water could be considered a _______________________ solution. A) concentrated B) dilute C) sat
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Answer:I believe your answer would be option B) dilute. Hope this helps.

Explanation:

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Answer: i would say D or the last one.

Explanation: According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

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Consider the reaction H2(g) + I2(g) <---> HI(g) with an equilibrium constant of 46.3 and a reaction quotient of 525. Which
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Answer:

The equilibrium will shift to the left to favor the reactants.

Explanation:

Remember that the reaction quotient (Qc) is derived from initial concentrations of reactants and products. Since Qc is greater than Kc, this means that initial concentrations are heavily impacted by a high product concentration ([HI]). Therefore, the reverse reaction will occur and actually create more reactants again ([H2] and [I2]). Thus, the answer is that the equilibrium will shift to the left side to favor the reactants.

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Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of alumin
Lerok [7]

<u>Answer:</u> The percentage yield of HF is 73.36 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ....(1)  

For calcium fluoride:

Given mass of calcium fluoride = 6.25 kg  = 6250 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium fluoride = 78.07 g/mol

Putting values in above equation, we get:  

\text{Moles of calcium fluoride}=\frac{6250g}{78.07g/mol}=80.05mol

For the given chemical reaction:

CaF_2+H_2SO_4\rightarrow CaSO_4+2HF

By Stoichiometry of the reaction:

1 mole of calcium fluoride produces 2 moles of hydrofluoric acid

So, 80.05 moles of calcium fluoride will produce = \frac{2}{1}\times 80.05=160.1mol of hydrofluoric acid

Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:

Moles of of hydrofluoric acid = 160.1 moles

Molar mass of hydrofluoric acid = 20.01 g/mol

Putting values in equation 1, we get:

160.1mol=\frac{\text{Theoretical yield of hydrofluoric acid}}{20.01g/mol}=3203.6g=3.20kg

To calculate the percentage yield of hydrofluoric acid, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of hydrofluoric acid = 2.35 kg

Theoretical yield of hydrofluoric acid = 3.20 kg

Putting values in above equation, we get:

\%\text{ yield of hydrofluoric acid}=\frac{2.35g}{3.20g}\times 100\\\\\% \text{yield of hydrofluoric acid}=73.36\%

Hence, the percentage yield of HF is 73.36 %

4 0
3 years ago
Calculate the mass in grams of a sample of Americium containing six atoms
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Americium has a molar mass of 243 g/mol.
There are 6.022*10^23 atoms in a mol (Avogadro's number).

6 atoms / 6.022 * 10^23 atoms/mol gives us:

9.963*10^-24 mols

Lastly: 9.963*10^-24 mols * 243 g/mol = 2.42*10^-21 g
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