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patriot [66]
3 years ago
10

The atomic number of an element is 71. is this element diamagnetic or paramagnetic?

Chemistry
2 answers:
Nonamiya [84]3 years ago
7 0

Answer:

Paramagnetic

Explanation:

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

Given the atomic number - 71

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^64d^{10}5s^25p^64f^{14}5d^16s^2

The electron in 5d orbital = 1

This 1 electron will be unpaired as electron is first singly filled.

<u>Thus, the element is paramagnetic as the electron is unpaired.</u>

Mrrafil [7]3 years ago
5 0
The  element  with atomic  number  71(lutetium) is  paramagnetic

  This  is  because  all  its   electrons   is  not  paired .  lutetium  has  electron  configuration  of  (Xe) 4f^14 5d^1 6S^2
Its 5d   sub shell  is  not  paired  since  the  d  sub shell  can  accommodate  a total  of  10   electrons  hence  lutetium  is  paramagnetic
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What is the electron configuration for<br> 08<br> 16
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The electron configuration for Oxygen : [He] 2s²2p⁴

<h3>Further explanation</h3>

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

• s: 2 electrons  

• p: 6 electrons  

• d: 10 electrons and  

• f: 14 electrons  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The element is Oxgen, with symbol O, and :

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The electron configuration based on the number of electrons(for Oxygen=8), so the configuration :

\tt _8^{16}O:1s^22s^22p^4 or we can write with noble gas [He] 2s²2p⁴

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