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djverab [1.8K]
3 years ago
11

When iron reacts with oxygen, it forms iron oxide, or rust.

Chemistry
1 answer:
Feliz [49]3 years ago
3 0

Answer:

Mass of iron oxide: 79.85 g  

Explanation:

Given data:

Mass of iron = 112 g

Mass of O₂ = 24 g

Mass of iron oxide formed = ?

Solution:

4Fe + 3O₂         →       2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/ molar mass

Number of moles = 112 g/ 55.85 g/mol

Number of moles =  2 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 24 g/ 32 g/mol

Number of moles =  0.75 mol

Now we will compare the moles of oxygen and iron with iron oxide.

                 Fe           :             Fe₂O₃

                 4             :                2

                 2             :                2/4×2 =  1

                O₂            :             Fe₂O₃

                 3             :                2

                 0.75       :                2/3×0.75 =  0.5

The number of moles of iron oxide formed by oxygen are less thus it will be limiting reactant.

Mass of iron oxide:

Mass = number of moles × molar mass

Mass = 0.5 mol  × 159.69 g/mol

Mass = 79.85 g  

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goldenfox [79]
I believe D. because all the organisms that live in a lake can be a bunch of living things that would be considered a population and not a species. I canceled out B. from the get go because, I don’t believe non living organisms can be in a population ?

Please get back to me if I’m right or wrong :)
5 0
2 years ago
Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves
hjlf

This is an incomplete question, here is a complete question.

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide:

2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)

In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide:

3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answer : The net chemical equation for the production of manganese is:

6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)

Explanation :

The given two chemical reactions are:

(1) 2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)

(2) 3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)

First we are multiplying reaction 1 by 3, and reaction 2 by 2, we get:

(1)

(2) 6MnO_2(s)+8Al(s)\rightarrow 6Mn(s)+4Al_2O_3(s)

Now we are adding both the reactions, we get the overall chemical reaction.

6MnCO_3(s)+3O_2(g)+6MnO_2(s)+8Al(s)\rightarrow 6MnO_2(s)+6CO_2(g)+6Mn(s)+4Al_2O_3(s)

The  MnO_2 is common on both side, by cancelling it, we get:

The net chemical equation for the production of manganese is:

6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)

5 0
3 years ago
15 points!
Alex_Xolod [135]

Answer:

C: It is the difference between the total kinetic and potential energy in a system.

Explanation:

6 0
3 years ago
Angiosperms produce brightly colored blooms and sweet-smelling flowers. Why have angiosperms developed these adaptations? A. to
blsea [12.9K]

Answer:

C

Explanation:

Angiosperms have developed these adaptations because it attracts pollinators which helps the ecosystem grow.

3 0
2 years ago
The digit that would have to be estimated in reading this instrument would be the nearest:
wariber [46]

Answer:

The least count of vernier calipers is 0.01 g.

(B) is correct option.

Explanation:

Given that,

The digit that would have to be estimated in reading this instrument,

According to figure,

We need to calculate the pitch

Using formula of pitch

pitch=\dfrac{distance\ moved}{Number\ of\ complete\ rotation}

Put the value into the formula

pitch=\dfrac{1}{10}

pitch=0.1\ g

We need to calculate the least count of vernier calipers

Using formula of least count

Least\ count=\dfrac{pitch}{number\ of\ vernier\ scale\ division}

Put the value into the formula

Least\ count=\dfrac{0.1}{10}

Least count = 0.01\ g

Hence, The least count of vernier calipers is 0.01 g.

(B) is correct option.

4 0
3 years ago
Read 2 more answers
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