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3 years ago

A Confession to my Friends

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer: Love is for the weak loll

artcher [175]3 years ago

7 0

Aww, that's sweet, but why don't you just text them?

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Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer

denis-greek [22]

Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.

Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave. You get $16.40. Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

3 0

3 years ago

On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?

bonufazy [111]

Answer:

Birds $F_b=14.3\%$

Gerbils $F_g=42.9\%$

Fish $F_f=21.4\%$

Hamsters $F_h=21.4\%$

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds $n_b=2$

Number of gerbils $n_g=6$

Number of fish $n_f=3$

Number of hamsters $n_h=3$

Generally the frequency for birds $F_b$ is mathematically given b

$F_b=\frac{n_b}{n}*100$

$F_b=\frac{2}{14}*100$

$F_b=14.3\%$

Generally the frequency for Gerbils $F_g$ is mathematically given b

$F_g=\frac{n_g}{n}*100$

$F_g=\frac{6}{14}*100$

$F_g=42.9\%$

Generally the frequency for fish $F_f$ is mathematically given b

$F_f=\frac{n_f}{n}*100$

$F_f=\frac{3}{14}*100$

$F_f=21.4\%$

Generally the frequency for fish $F_h$ is mathematically given b

$F_h=\frac{n_h}{n}*100$

$F_h=\frac{3}{14}*100$

$F_h=21.4\%$

5 0

3 years ago

Is -¼ + 2 ¼y + 2 - y equivalent to y + 2 ?

Juliette [100K]

Answer: No

Step-by-step explanation:

$-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2$

$(-\frac{1}{4}+2)+(2\frac{1}{4}y-y)=y+2\\$

$(\frac{(-1)+(4)(2)}{4})+(\frac{9}{4}y-y)=y+2$

$(\frac{-1+8}{4})+(\frac{(9)(1)-(4)(1)}{4} )y=y+2$

$(\frac{7}{4})+(\frac{9-4}{4} )y=y+2$

$(\frac{7}{4})+(\frac{5}{4})y=y+2$

5 0

3 years ago

Mr. Hans wants to give an award to the student with the best jump rope rate. Linda can jump rope 120

Gelneren [198K]

Answer:

c) Mike receives the award for being the best at jumping rope.

Step-by-step explanation:

Here, according to the question

Jumping rate of Linda = 120 times in 4 minute

So, number of jumps Linda does per minute = (120/4) = 30

So, Jumps per minute of Linda is 30.

Jumping rate of Carl = 315 times in 9 minute

So, number of jumps Carl does per minute = (315/9) = 35

So, Jumps per minute of Carl is 35.

Jumping rate of Mike = 252 times in 7 minute

So, number of jumps Mike does per minute = (252/7) = 36

So, Jumps per minute of Linda is 36.

Now if we compare the <u>jumps per minute</u> of Linda , Carl and Mike, weget that Mike has the best rate of 36 jumps per minute.

Hence, Mike receives the award for being the best at jumping rope.

4 0

3 years ago

Whoever gets this in 5 mins will be brainlest

ivanzaharov [21]

Answer:

easy its c

Step-by-step explanation:

so you do you start with the left 2 to the third power is 8

then the right side now is -3 to the second power is -9

in total 8- (9-)

so your answer is -1

hope this helps

8 0

2 years ago

Read 2 more answers