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faltersainse [42]
3 years ago
12

Look at the table below. Plot and label points M and N on the coordinate plane below. Then write ordered pairs for points M and

N and describe how to move from (0, 0) to each point.

Mathematics
1 answer:
disa [49]3 years ago
5 0
M = one unit to the right and four units up.
N = five units to the right and two units up

(to solve these type of questions just plot it first then label what you did in order to plot it in the format i just did) hope that helps :)
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4 years ago
1. What is the value of the expression 3^-4?. a) -81. b) -12. c) -1/81. d) 1/81. 2. What is the value of the expression 1/4^3?.
hjlf

Answer:

1.

Option d is correct

2.

Option c is correct

3.

Option a is correct

4.

Option d is correct

5.

Option c is correct

Explanation:

Using exponent rule:

a^{-n} = \frac{1}{a^n}

1.

Given the expression:  

3^{-4}

Apply the exponent rules:

\frac{1}{3^4} = \frac{1}{81}

Therefore,  the value of the given expression is, \frac{1}{81}.

2.

To find the value of the expression \frac{1}{4^3}

then;

\frac{1}{4^3} = \frac{1}{64}

Therefore, the value of the given expression is, \frac{1}{64}.

3.

Find the the value of the expression \frac{2}{4^3}

then;

\frac{2}{4^3} = \frac{2}{64}

Simplify:

\frac{1}{32}

Therefore, the value of the given expression is, \frac{1}{32}.

4.

Given the expression:

K^{-3} = \frac{1}{27}

we can write this as:

K^{-3} = \frac{1}{3^3}

Apply the exponent rules:

K^{-3} = 3^{-3}

On comparing both sides we have;

K = 3

Therefore, the value of K is, 3

5.

Given the expression:

3^N= \frac{1}{81}

we can write this as:

3^N= \frac{1}{3^4}

Apply the exponent rules:

3^N = 3^{-4}

On comparing both sides we have;

N = 4

Therefore, the value of N is, -4

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4 years ago
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