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alexira [117]
3 years ago
5

Consider the following pair of equations:

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
There is a special kind of substitution which some books call it by comparison.

When the two equations are both 
y=some function of x
y=some other function of x, then
we can substitute the second equation into the first giving
some function of x = some other function of x and start solving.

For example,
<span>y = –2x + 8 
y = x – 1
substitute second into first
x-1=-2x+8
isolate x on left,
3x=9
x=3
second step is to substitute x=3 into second equation to get
y=x-1=3-1=2
Therefore the solution is (3,2)</span>
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Lexi mailed a letter on Monday morning. The letter traveled 1/2 of a mile on Monday. It
BartSMP [9]

Answer:

1 1/4 miles

Step-by-step explanation:

3/4 + 2/4 (1/2 = 2/4) = 5/4 = 1 1/4

3 0
2 years ago
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Factor completly: x^2-2x-24
melisa1 [442]
<span>x^2-2x-24 = (x - 6)(x + 4)

cause
</span>(x - 6)(x + 4)
= x^2 - 6x + 4x - 24
= x^2 - 2x - 24

answer
(x - 6)(x + 4)

hope it helps
4 0
3 years ago
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Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t
horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

\left[\begin{array}{ccc}4\\3\end{array}\right]

The transformation Matrix is:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

The image of the vector after applying the transformation will be:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]

The correct option is C

7 0
3 years ago
Please help.... fast​
zloy xaker [14]

Answer:

<h2>HL</h2>

Step-by-step explanation:

It tells you the triangle is a right triangle and it tells you that the hypotenuse of both triangles is congruent.

I'm confident that this is the answer.

8 0
2 years ago
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle
Rus_ich [418]

Answer:

y = negative four-thirds x + StartFraction 31 Over 3 EndFraction

y = 2 x + 7

Step-by-step explanation:

Let x represent the smaller number and y represent the larger number.

<h2><u /></h2><h2><u>Part 1</u></h2>

Four times a number added to 3 times a larger number is 31.

<u>It is translated as:</u>

  • 4x + 3y = 31

<u>Then, solving for y:</u>

  • 4x + 3y=31 ⇒ 3y= -4x+31 ⇒ y= (-4x+31)/3 = - 4/3x + 31/3

    ⇒  y= - 4/3x + 31/3

<u>Correct answer choice for this equation:</u>

y = negative four-thirds x + StartFraction 31 Over 3 EndFraction

<h2><u>Part 2 </u></h2>

Seven subtracted from the larger number is equal to twice the smaller number.

<u>It is translated as:</u>

  • y-7= 2x

<u>Then, solving for y:</u>

  • y-7= 2x ⇒ y= 2x+ 7

<u>Correct answer choice for this equation:</u>

y = 2 x + 7

4 0
2 years ago
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