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MA_775_DIABLO [31]
3 years ago
7

PLESE HELP ME RN PLEASE

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

16+3x=22.75

22.75-16=6.75

6.75÷3=2.25=x

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Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
Try to find the answer to the following inequality.<br> +4n-1&lt;+6n+9-8n+15<br> what is n?
Alik [6]
It’s 8 cuz u switch them
6 0
3 years ago
The function f is such that f(x) = 2x/3x+5 The function g is such that g(x) = 3/x+4 Find fg(-5)
White raven [17]

Answer:

f(g(-5)) = \frac{3}{2}

Step-by-step explanation:

Given

f(x) = \frac{2x}{3x+5}

g(x) = \frac{3}{x+4}

Required

Find f(g(-5))

First, we calculate f(g(x))

f(x) = \frac{2x}{3x+5}

Substitute g(x) for x

f(g(x)) = \frac{2g(x)}{3g(x) + 5}

Substitute \frac{3}{x+4} for g(x)

f(g(x)) = \frac{2*\frac{3}{x+4}}{3*\frac{3}{x+4} + 5}

f(g(x)) = \frac{\frac{6}{x+4}}{\frac{9}{x+4} + 5}

f(g(x)) = \frac{6}{x+4}/ (\frac{9}{x+4} + 5})

Take LCM

f(g(x)) = \frac{6}{x+4}/ \frac{9+5x+20}{x+4}}

f(g(x)) = \frac{6}{x+4}/ \frac{5x+29}{x+4}}

Rewrite as multiplication

f(g(x)) = \frac{6}{x+4}* \frac{x+4}{5x+29}}

f(g(x)) = \frac{6}{5x+29}

Substitute -5 for x

f(g(-5)) = \frac{6}{-5*5+29}

f(g(-5)) = \frac{6}{-25+29}

f(g(-5)) = \frac{6}{4}

f(g(-5)) = \frac{3}{2}

5 0
3 years ago
Use the distributive property to find the product of 26 x 2 1/2
Alinara [238K]
Do not know sorry I hope someone will help I guess 34
6 0
3 years ago
For every 7 glasses wearers in a Classroom,there are about 13 non glasses wearers.If there are 32 students in a entire class how
mars1129 [50]
The answer is 11, How I got my answer.

First I added 7+13=20, so now I can find the percentage, which is 35% of 20=7, so then I found that 35% of 32=11.2, so now I just round it off.

I hope this helps!
5 0
3 years ago
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