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BabaBlast [244]
3 years ago
14

What is 4/7 multiplied by 13/9

Mathematics
1 answer:
nevsk [136]3 years ago
4 0

Answer:

52/63

Step-by-step explanation:

Here, we want to multiply two fractions

we have this as;

4/7 * 13/9

= 52/63

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A + B
Klio2033 [76]

Answer:

A= 0.5 and B= 4040

Step-by-step explanation:

If you write out the equation and rearrange a little it gets easier to understand.

( a + b) + (a*b) + (a - b)  you can rewrite this as

a + b + a - b + (a*b)  this is the same as 2a + ab = 2021

The way I looked at it is to figure out how to get that number 1 at the end.

The number 2020 is easy to get to.  How can you get the number 1 using either 2a or ab.

I looked at a = 0.5.   2 times 0.5 would be 1.

So now what would b have to be?  We can get the 1 at the end with the 2a part of the equation so now we have to get ab = 2020.

b = 2020/a  which using our a = 0.5, you can see that b would have to equal 4040.  Test it all out in your equation.

0.5 + 4040 + (0.5 * 4040) + 0.5 - 4040

4040.5 + (2020) - 4039.5 = 2021

So A = 0.5  and B = 4040

4 0
3 years ago
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
3 years ago
Sarah made two dozen
alex41 [277]
Answer: 6.28 cm

Explanation: The radius of a circle is half of the diameter, therefore you divide the diameter by two to find the radius.
3 0
3 years ago
ZA and ZB are supplementary angles. If mZA = (5x + 25)° and m
liberstina [14]

Answer:

MZA = 140

Step-by-step explanation:

5x+25°+ x + 17°=180°(Supplimentary Angles)

6x + 42° =180°

6x =180 - 42

6x=138

(divide by 6 both sides)

X= 23

substitution X into the given angle

5x +25

5(23)+25

115+25

140

3 0
2 years ago
Determine ſ(2) where f(x) =x+1/4x-2
umka2103 [35]
F(X)= x+1/4x-2
f(2) = (2 + 1)/[(4)(2) - 2]
f(2) = 3/6 = 1/2
6 0
2 years ago
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