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2 years ago

What is 4/7 multiplied by 13/9

Mathematics

1 answer:

nevsk [136]2 years ago

4 0

Answer:

52/63

Step-by-step explanation:

Here, we want to multiply two fractions

we have this as;

4/7 * 13/9

= 52/63

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Solve the equation x2<br> 18x + 21 = -3x to the nearest tenth.

Bumek [7]

Answer:

1x=-29

2x=-1

Step-by-step explanation:

i hope its useful.

7 0

2 years ago

WILL GIVE BRAINLIEST!! FINALS!

GenaCL600 [577]

Factor completely x³ + 6x² - 3x – 18
$- 6 + 6( - 6)^{2} - 3( - 6) - 18 \\ - 6 +6 \times 6 ^{2} + 18 - 18 \\ - 6 + 6 ^{3} + 18 - 18 \\ - 6 + 216 \\ 210$
with a root of x = -6

the answer is 210

3 0

3 years ago

6. f(x) = x ^ 2 + 2x g(x) = 3x ^ 2 - 1

AVprozaik [17]

Answer:

3x^2+1

Step-by-step explanation:

7 0

3 years ago

What is the surface area of the regular pyramid given below?

VARVARA [1.3K]

Each trianglar side has an area: (1/2)*8*9=36
the base is a square with an area of 8*8=64
so the total surface area is 36+36+36+36+64=208

5 0

3 years ago

Read 2 more answers

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago

What is 4/7 multiplied by 13/9￼

What is 4/7 multiplied by 13/9