First of all, assuming that the "ground level" is 0;
The lift is not starting from 0, so we also need to account for the extra 15 meters above the ground the lift is.
The total distance the lift would cover in the downward direction: 15+350=365m
Now, you know that the lift covers 5 m/min
Therefore, 5x=365 (ignoring units because they can complicate things)
x=365/5
x=73 minutes
Therefore, they would take 73 minutes to reach 350 m deep into the ground with a starting position 15 m above the ground.
Hope I helped :)
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
The number between 4 and -7 is -3/2, so no, the answer is (2, -3/2) which is B
Answer:
We simplify the equation to the form, which is simple to understand
5x+15=4x-12
We move all terms containing x to the left and all other terms to the right.
+5x-4x=-12-15
We simplify left and right side of the equation.
+1x=-27
then divide both sides of the equation by 1 to get x.
x=-27
Answer:
x = 11 units
Step-by-step explanation:
Area of triangle = (base + base 2) * h *1/2
so (7 + x )* 7 * 1/2 = 63
63 x 2 = 126
126 / 7 = 18
18-7 = x
x = 11
Check
(7+11)* 7 * 1/2
18* 7 = 126
126 x 0.5 = 63
CORRECT!
(p.s., tell me if wrong :P)
