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Dmitry [639]
3 years ago
7

Write the two consecutive whole numbers that the quotient for 96 ÷ 19 is between

Mathematics
1 answer:
joja [24]3 years ago
8 0
<span>Write the square numbers between 1 and 40. describe the patterns the square numbers ... HOW DO I FIND OUT WHAT The sum of three consecutive natural numbers is 870, find the numbers .... and median are both 19.what numbers could be the values in the data set? i got: 14 19 25. .... The quotient of two numbers is 46.</span><span>
</span>
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Help please explain and answer thanks
enot [183]
Im there so what math problem
4 0
3 years ago
Consider the enlargement of the pentagon. A small pentagon has a bottom side length of x centimeters and left side length of 7 c
LuckyWell [14K]

When the pentagon is drawn to scale then its value of x will be x=3.3 cm

<h3>What is the pentagon?</h3>

The pentagon is defined as the shape having five sides connected together.

Now it is given in the question that

For small pentagone

Bottom =x

left =7 cm

For larger pentagone

Bottom=7cm

left=15cm

Now since the pentagon is actually dilated from its size to the new bigger size. It means that the equivalent ratio of both the pentagons will be equal.

For smaller pentagon

\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{x}{7}

For bigger pentagon

\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{7}{15}

Since both, the ratio is the same

\dfrac{x}{7} =\dfrac{7}{15}

x=\dfrac{49}{15} =3.3\ cm

Thus the pentagon is drawn to scale than its value of x will be x=3.3 cm

To know more about Pentagone follow

brainly.com/question/4804571

4 0
2 years ago
Find a recursive formula for the sequence:<br><br> 1, -1, -7, -25
Mumz [18]
<h3>Answer:</h3>

a_n=3a_{n-1}-4

<h3>Step-by-step explanation:</h3>

<em>Try the answers</em>

You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.

a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works

b) -7 -2 = -9 . . . . ≠ -25

c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25

d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25

The formula that works is the first one.

_____

<em>Derive it</em>

All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...

a_n=p\cdot a_{n-1}+q

Then, to get the second term from the first, we have

... 1·p +q = -1

And to get the third term from the second, we have

... -1·p +q = -7

Subtracting the second equation from the first gives ...

... 2p = 6

... p = 3 . . . . . . . this is sufficient to identify the first answer as correct

We can find q from the first equation.

... q = -1 -p = -1 -3 = -4

So, our recursion relation is ...

a_n=3a_{n-1}-4

6 0
3 years ago
Test 69,000 on hearing to for divisibility by 2 3 5 9 or 10
svetoff [14.1K]
Yes they are correct
7 0
3 years ago
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
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