Question

Daniel drew a toy from a treasure chest containing 30 different toys. He selected a bouncy ball without replacement and then selected a key chain. What is the probability this could occur

Answer 1

Answer:

$Pr = \frac{1}{870}$

Step-by-step explanation:

Given

$n =30$

Required

Probability of selecting 2 toys of different types

From the question, we understand that all toys are different i.e. 1 of each type.

And the selection is without replacement;

So, after the first toy is selected; there are n - 1 toys left.

So, the probability is:

$Pr = \frac{1}{n} * \frac{1}{n - 1}$

Substitute $n =30$

$Pr = \frac{1}{30} * \frac{1}{30- 1}$

$Pr = \frac{1}{30} * \frac{1}{29}$

$Pr = \frac{1}{30*29}$

$Pr = \frac{1}{870}$