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bija089 [108]
4 years ago
11

What is the command to use the memory diagnostics tool?

Computers and Technology
1 answer:
Shalnov [3]4 years ago
8 0
The <span>mdsched.exe tool can be used all the way to XP to diagnose your memory.</span>
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A user brings a technician a mobile device that has no sound. What should a technician check for first?
Mashutka [201]
The volume is muted seems to be correct
3 0
3 years ago
Database software lets the user sort information alphabetically, chronologically, or numerically. Which is NOT a commonly used d
vlabodo [156]
 it is a paradox .......... 
8 0
4 years ago
Find the smallest value of n such that LCM of n is 15 is 45​
raketka [301]

Answer:

n=9

Explanation:

LCM(n,15)=45

LCM(9,15)=45

8 0
3 years ago
Monster Collector
Lera25 [3.4K]

Answer:

In java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int monsternum, usernum;

 int count = 0;

 Random rand = new Random();

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

 for(int i =0;i<2;i++){

     monsternum = rand.nextInt(5);  

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

     usernum = input.nextInt();

     if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  }

 else{      System.out.println("You almost had it, but the monster escaped.");  }

 

 }

 System.out.println("There are no more monsters to encounter!");

 System.out.println("You caught "+count+" monsters of 2");

 if(count!=2){      System.out.print("Keep training to be the very best!");  }

 else{      System.out.print("You're the monster collector master!");  }

}

}

Explanation:

This declares monster and user number as integers

 int monsternum, usernum;

Initialize count to 0

 int count = 0;

Call the random object

 Random rand = new Random();

Create a string array to save the monster names

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

Iterate for the 2 monsters

 for(int i =0;i<2;i++){

Generate a monster number

     monsternum = rand.nextInt(5);  

Prompt the user to take a guess

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

Get user guess

     usernum = input.nextInt();

If monster number and user guess are equal, congratulate the user and increase count by 1

<em>      if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  } </em>

If otherwise, prompt the user to keep trying

<em>  else{      System.out.println("You almost had it, but the monster escaped.");  }  </em>

<em>  } </em>

Print no monsters again

 System.out.println("There are no more monsters to encounter!");

Print number of monsters caught

 System.out.println("You caught "+count+" monsters of 2");

Print user score

<em>  if(count!=2){      System.out.print("Keep training to be the very best!");  } </em>

<em>  else{      System.out.print("You're the monster collector master!");  } </em>

5 0
3 years ago
MinMax is a function that takes five arguments and returns no value. The first three arguments are of type int. The last two arg
Luba_88 [7]

Answer:

#include <iostream>

using namespace std;

void MinMax(int x,int y,int z,int *max,int *min)

{

   int big,small;

   if((x>y)&&(x>z))    //to check for maximum value

       big=x;

   else if((y>x)&&(y>z))

       big=y;

   else

       big=z;

   if((x<y)&&(x<z))  //to check for minimum value

       small=x;

   else if((y<x)&&(y<z))

       small=y;

   else

       small=z;

   *max=big;   //pointer pointing to maximum value

   *min=small;     //pointer pointing to minimum value

}

int main()

{

   int big,small;

   MinMax(43,29,100,&big,&small);    

   cout<<"Max is "<<big<<"\nMin is "<<small;  //big and small variables will get value from method called

   return 0;

}

OUTPUT :

Max is 100

Min is 29

Explanation:

When the method is called from first three integers maximum will be found using the conditions imposed and maximum value will be found and similarly will happen with the minimum value.

5 0
3 years ago
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