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3 years ago

Use the factor theorem to determine if the given binomial is a factor of f (x).

Mathematics

1 answer:

oee [108]3 years ago

8 0

Answer:

The binomial is a factor

Step-by-step explanation:

In order to show that x+3 is a factor of the polynomial, then;

f(a) = 0

Get a by equating x+3 to zero

x+3 = 0

x = -3

Get f(-3)

f(-3) = (-3)^4 + 8(-3)^3 + 11(-3)^2 -11(-3) + 3

f(-3) = 81 - 216 + 99 + 33 + 3

f(-3) = 216-216

f(-3) = 0

Since the remainder of the polynomial when divided by x+3 is zero, this shows that x+3 is a factor of the given polynomial

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zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

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3 years ago

3 kom 2.7 Eve carves a shape out of wood. What is the volume of the shap 3 cm 1 cm 2 cm 3 cm 4 cm

Mariana [72]

Answer:

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Step-by-step explanation:

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3 years ago

The difference of n and 7 is no more than 12. Find all possible values of n.

WINSTONCH [101]

Answer:

-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29

7-12= -5

7+12= 29

-5 ≤ n ≤ 29 or -5 ≤ n < 30 or -6< n ≤ 29 or -6 < n < 30

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2 years ago

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The midpoint of xy is located at the origin

klio [65]

Answer:

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Step-by-step explanation:

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3 years ago

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The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

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3 years ago