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3 years ago

8

Please help! im struggling

1 answer:

ANEK [815]3 years ago

8 0

3. x=0 y= 3
4. x=-2 y=3

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19, find the direction angle of vector v to the nearest tenth of a degree

labwork [276]

The vector v is given by:
v = (7, 2) - (-5, 0)
v = ((7 - (- 5)), (2-0))
v = ((7 + 5), 2)
v = (12, 2)
Then, the angle is given by:
tan (theta) = 2/12
theta = atan (2/12)
theta = 9.46 degrees
Answer:
The direction angle of vector to the nearest tenth of a degree is:
theta = 9.5 degrees

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3 years ago

The consumer price index is

nikklg [1K]

Answer:

A tool to measure the changes in the prices of weighted average market basket of goods and services purchased by consumers, usually households.

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3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

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3 years ago

Two pools are being filled with water. To start, the first pool had 728 liters of water and the second pool was en pty. Water is

vredina [299]

Answer:

52 minutes

Step-by-step explanation:

Equation:

$728+23x=0+37x\\728+23x=37x\\728=14x\\x=52$

So 52 minutes.

Hope this helps plz hit the crown :D

7 0

2 years ago

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The radius of the large sphere is double the radius of the small sphere. How many times is the volume of the large sphere than t

kobusy [5.1K]

The volume of a sphere is $\cfrac{4}{3}\ \pi r^3$

So, if the small sphere has radius $r$ and the largest sphere has radius $2r$ , their volumes are

$V_1 = \cfrac{4}{3}\ \pi r^3,\quad V_2 = \cfrac{4}{3}\ \pi (2r)^3 = \cfrac{4}{3}\ \pi 8r^3$

So, their ratio is

$\cfrac{V_2}{V_1} = \cfrac{\frac{4}{3}\ \pi 8r^3}{\frac{4}{3}\ \pi r^3} = 8$

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3 years ago

Read 2 more answers