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3 years ago

Which of the following represents 2x - 5y + 15 = 0 written in slope-intercept form?

Mathematics

1 answer:

arsen [322]3 years ago

8 0

R those the only options?
slope intercept form is y=mx+b
i got y = 2/5x + 3

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The functions f(x) and g(x) are shown below:

Flura [38]

Answer:

(A) is your answer. The graph of g(x) will eventually exceed the graph of f(x)

Step-by-step explanation:

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Find slope for 3y=-4x+6 please help asap :)

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Answer: the slope would be -4/3 and the y intercept is 2

Step-by-step explanation: you would have to divide both sides by 3 to get y by itself. that leaves you with -4/3x + 2

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Emissions of sulfur dioxide by industry sett off chemical changes in the atmosphere that result in "acid rain". The acidity of l

horsena [70]

Answer:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P value

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

Step-by-step explanation:

Data given and notation

$\bar X=4.8$ represent the sample mean

$\sigma=0.5$ represent the population standard deviation

$n$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:

Null hypothesis: $\mu \geq 5$

Alternative hypothesis: $\mu < 5$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P-value

Since is a left tailed test the p value would be:

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

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4 years ago

I need help with this question

dybincka [34]

Answer:

1) 144

2) 1

Step-by-step explanation:

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3 years ago

Applicants who wish to be admitted to a certain professional school in a large university are required to take a screening test

Elden [556K]

Answer:

Probability of eligible applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

Step-by-step explanation:

Total percentage eligible applicants who pass the exam

$\textrm {89\% of 70\%}= \dfrac{89\times70}{100}=62.3\%$

Total ineligible applicants who pass the exam

$\textrm {14\% of 30\%}= \dfrac{14\times30}{100}=4.2\%$

All applicants who pass this exam 62.3% + 4.2% = 66.5%

Probability of applicants who pass the exam

$\textrm{probability }= \dfrac{66.5}{100}=0.665$

Out of 66.5% applicants who pass the exam , 4.2% applicants are ineligible

$\textrm{so the probability is}\dfrac{4.2}{66.5}=0.063$

Probability of applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

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3 years ago