Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
Answer:
y = -0.07x2 + 3.07x
Step-by-step explanation:
For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.
So, for 2 plants, we have (3 - 0.07) * 2
For 3 plants, we have (3 - 2*0.07) * 3
For x plants, we have (3 - (x-1)*0.07) * x
So we can model the final result of the amount of beans 'y' with the equation:
y = (3 - (x-1)*0.07) * x
y = (3 - 0.07x + 0.07) * x
y = (3.07 - 0.07x) * x
y = -0.07x2 + 3.07x
(In this equation we have a = -0.07, b = 3.07 and c = 0)
Answer:
17.85
Step-by-step explanation:
just times 5.95 by 3
Answer:
x < -33 ( mark me as the brainliest )
Step-by-step explanation:
1) -4x > 132
2) -4x/4 > 132/-4
3) x < -33
