The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
learn more on sequence here: brainly.com/question/24128922
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Answer:
f(7) = 158
Step-by-step explanation:
To evaluate f(7) substitute t = 7 into f(t)
f(7) = 3(7)² + 11 = (3 × 49) + 11 = 147 + 11 = 158
8*4=32
7*4=28
340÷32=10.625
350÷28=12.5
12.5-10.625= 1.875
Q1 = (19 + 20)2 = 19.5
Q2 = 26
Q3 = (32 + 33)/2 = 32.5
IQR = 32.5 - 19.5 = 13
13 * 1.5 = 19.5
outliers are : 19.5 - 19.5 = 0...anything below 0
32.5 + 19.5 = 52...anything above 52
there are no outliers <====
