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2 years ago

T2.T?

Mathematics

1 answer:

Setler [38]2 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

Reversing the digits changes the value by a factor of 9 times the difference in the digit values. Here, this means the digits differ by 27/9 = 3. If one digit is double the other, the higher digit is 2×3 = 6.

The number is 63.

_____

If you like, you can work through the algebra of it. Let the original number have tens digit x and ones digit y.

original number value = 10x +y

reversed number value = 10y +x

difference of values = 27 = (10x +y) -(10y +x) = 9(x -y)

The tens digit is twice the ones digit, so we have ...

x = 2y

Substituting in the difference equation, we have ...

27 = 9(x -y)

3 = (2y -y) = y . . . . . divide by 9, substitute for x

x = 2(3) = 6

The number is 10x+y = 63.

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Nataly_w [17]

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|18-x|, if x<18. Pls help

damaskus [11]

Answer:

I18 - xI such that x < 18.

ok, first let's what happens if x = 18:

I18 - xI = I18 - 18I = 0

So, at the moment we have the condition:

I18 - xI > 0.

now, if x is a really large negative number, suppose, x = -100

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2 years ago

35. A can of popcorn is to be packed in a box for shipping as shown. The can is 18 inches tall and has a radius of 7 inches. The

lianna [129]

The amount of packing material is 1506 cubic inches

<h3>How to determine the amount of packing material?</h3>

The given parameters are:

Radius, r = 7 inches

Height, h = 18 inches

Base dimension, l = 15 inches

Height, h = 19 inches

The volume of the can is:

$V = \pi r^2h$

So, we have:

$V_1 = 3.14 * 7^2 * 18$

$V_1 = 2769$

The volume of the box is

$V =l^2h$

So, we have:

$V_2 =15^2 * 19$

$V_2 =4275$

The amount of packing material is;

Amount = V2 - V1

This gives

Amount = 4275 - 2769

Evaluate

Amount = 1506

Hence, the amount of packing material is 1506 cubic inches