Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.


The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Answer:
I missed the part where that's my problem
Kaleerain5,
In order to get your answer you must remember that if the exponent is negative move to the left and if the exponent is positive you have to move to the right.

- The exponent is negative so move to the left:


Therefore your answer is ".000857."
Hope this helps!
Answer:
8/3x + 6 (first option)
Step-by-step explanation:
Well youc an use the destructive property, multiply 2/3 with each number in this expression
2/3* 4x= 8/3x
and
2/3 *9 is 6
Now just plug it in as usual
8/3x+6
The answer is $8.43 for this question