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Molodets [167]
3 years ago
7

I need help with internet’s I am not doing good in math and I really need help

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

Then get some help

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Hello good day <br>can you help me please:(​
iVinArrow [24]

Answer:

31. A

32. D

33. B

4 0
1 year ago
In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p
sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}

We know that formula for permutations is given as

_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}

On substituting the given values in the formula we get,

{_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}

=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\&#10;\\&#10;=35\cdot 34\cdot 33=39270

Therefore, there are 39270 ways in which prizes can be awarded.


6 0
3 years ago
Simplify: (32x2/5y5)1/5
masya89 [10]
The answer is 64/5 xy

4 0
3 years ago
This is how you solve this problem: 4/5 = 3 = 4/5 x 3<br> True<br> False
ivann1987 [24]

Answer:

false

Step-by-step explanation:

because when solving fraction as a equation you divide

6 0
2 years ago
Which operation will make the llower left element the largest?
algol [13]

Answer:

R2->R3

Step-by-step explanation:

3 0
3 years ago
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