9514 1404 393
Answer:
(d) 5a²
Step-by-step explanation:
![\displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B125a%5E6%7D%3D%5Csqrt%5B3%5D%7B5%5E3a%5E6%7D%3D%5Csqrt%5B3%5D%7B%285a%5E2%29%5E3%7D%3D%5Cboxed%7B5a%5E2%7D)
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The applicable rules of exponents are ...
(a^b)^c = a^(bc)
∛a = a^(1/3)
If you're talking about the soccerball to football one, it would be a
Answer:
|-8|
if you are happy with my answer, please give brainliest :)
Step-by-step explanation:
Absolute value of -8 is 8, which is greater than the other values.
We presume you want to find the number.
Let n represent the number.
6 + n/4 = 3 . . . . . . . 6 more than the quotient of a number and 4 is 3.
To solve this, we "undo" what is done to the number. First we undo the addition of 6 by adding its opposite, -6. We add -6 to both sides of the equation so the equal sign remains valid.
6 -6 +n/4 = 3 -6
n/4 = -3 . . . . . . . . simplify
Now, we need to undo the division by 4. We do that by multiplying by 4. Again, we must do that to both sides of the equation so the equal sign remains valid.
4(n/4) = 4(-3)
n(4/4) = -12
n = -12
The number is -12.
Answer:
500,000
Step-by-step explanation:
