Question

y= x^2-2x+2 complete the square to determine the vertex and maximum or minimum value. Determine the number of x-intercepts.

Answer 1

Answer:

Step-by-step explanation:

y = x^2 - 2x + 2

y = (x - 1)^2 - 1 + 2

y = (x - 1)^2 + 1

Vertex is at (1, 1) and minimum value is  1.