1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natulia [17]
3 years ago
11

What is WEB 1.0 to WEB3.0

Computers and Technology
1 answer:
Allushta [10]3 years ago
3 0
It's a marketing term. Web1.0 is the www as a static resource of pages and documents. Web2.0 adds interactivity, scripting and databases. Web3.0 suggests semantic integration of different sources, like single sign-on. Not many 3.0 elements exist today.
You might be interested in
How do you measure objects and re-size them in tinkercad? I need it in steps.
Luda [366]


How do I modify it so that it is wider and longer by a few millimeters but the screw holes stay the exact same size? Additionally the angle of the upper surface must stay the same. Please suggest the easiest solution for someone like me who as no idea about CAD software.

4 0
3 years ago
What does it mean to catch an exception?
Vikentia [17]

Answer:

An exception is an event, which occurs during the execution of a program, that disrupts the normal flow of the program's instructions. When an error occurs within a method, the method creates an object and hands it off to the runtime system. ... This block of code is called an exception handler.

5 0
3 years ago
PLEASE HELP! One of the nice byproducts of joining a club, organization, community service project, or service learning project
astra-53 [7]
A hope I help ya out:))
8 0
3 years ago
Choose the term that matches each description.
lutik1710 [3]

Answer:

operating systems, word software, computer concepts for end users

Explanation:

operating systems allow users to interact with computer hardware and application software.

word software allows users to complete specific tasks, such as creating a document.

computer concepts for end users allows programmers to create new applications.

7 0
2 years ago
Does the estimate of a tolerance level of 68.26% of all patient waiting times provide evidence that at least two-thirds of all p
ivanzaharov [21]

Answer:

Yes, because the upper limit is less Than 8 minutes

Explanation:

According to the empirical formula :

68.26% of data lies within 1 standard deviation from the mean;

Hence,

Mean ± 1(standard deviation)

The sample mean and sample standard deviation of the given data is :

Sample mean, xbar = Σx / n = 546 / 100 = 5.46

Sample standard deviation, s = 2.475 (Calculator)

The interval which lies within 68.26% (1 standard deviation is) ;

Lower = (5.460 - 2.475) = 2.985

Upper = (5.460 + 2.475) = 7.935

(2.985 ; 7.935)

Since the interval falls within ; (2.985 ; 7.935) whose upper level is less than 8 means patients will have to wait less Than 8 minutes.

8 0
3 years ago
Other questions:
  • Write a MATLAB script using the quiver and contour commands to visualize the field and its divergence. Assume the region of inte
    12·1 answer
  • A computer that delivers requested webpages to your computer or mobile device is a(n) _________.
    9·1 answer
  • You have no control over who views your social network information
    13·2 answers
  • A tornado may be approaching if you observe which of the following?
    15·1 answer
  • What does PowerPoint display when you use the Notes Page view?
    14·2 answers
  • What is the analysis stage in System development life cycle?
    12·1 answer
  • Nikolas has a idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard. Nikol
    13·2 answers
  • You want to substitute one word with another throughout your document. What tool(s) should you use?
    9·1 answer
  • Features of Python are *
    9·1 answer
  • What is the descriptor for a filter that warns or blocks you from potentially fraudulent or suspicious websites?.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!