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3 years ago

Domain of a relation

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

8 0

Answer:

All of the values that can go into a relation or function (input) are called the domain. ... The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

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You flip a coin that is not fair, the prbability of heads on each flip is 0.7. if the coin shows heads, you draw a marble from u

Shkiper50 [21]

Solution :

P(H) = 0.7 ; P(T) = 0.3

If heads, then Urn H, 1 blue and 4 red marbles.

If tails, then Urn T , 3 blue and 1 red marbles.

a).

P ( choosing a Red marble )

= P (H) x P( Red from Urn H) + P (T) x P( Red from Urn T)

$=0.7 \times \frac{4}{5} + 0.3 \times \frac{1}{4}$

= 0.56 + 0.075

= 0.635

b). If P (B, if coin showed heads)

If heads, then marble is picked from Urn H.

Therefore,

P (Blue) $=\frac{1}{5}$

= 0.2

c). P (Tails, if marble was red)

$=P (T/R) = \frac{P(R/T)}{P(R)} \ P(T)$

Where P (R/T) = P ( red, if coin showed tails)

$=\frac{1}{4}$

= 0.25 (As Urn T is chosen)

P (R) = P (Red) = 0.635 (from part (a) )

P (T) = P (Tails) = 0.3

∴ $P(T/R) = \frac{0.25 \times 0.3}{0.635}$

= 0.118

8 0

3 years ago

Find the 12th number in the sequence below<br> 1/2, 1/10, 1/18, ...

Sergio [31]

Answer:

1/90.

Step-by-step explanation:

the pattern goes up by eight.

it would continue like so:

1/2, 1/10, 1/18, 1/26, 1/34, 1/42, 1/50, 1/58, 1/66, 1/74, 1/82, 1/90.

1/90 would be the 12th number in the sequence.

7 0

3 years ago

The estimated number of organisms in a population after t days is shown in the table below. t days estimated number of organisms

Lelu [443]

Answer:

The function $n=591.68(1.2056)^t$ best models the situation.

Step-by-step explanation:

The values in the table do not lie over a straight line because their slope is not a constant; for example

$m_1=\frac{1250=860}{4-2} =195$

$m_2=\frac{1850-1250}{2}=275$

we see here that $m_1\neq m_2$ therefore a linear equation cannot represent this situation.

The values in the table are increasing exponentially , therefore the equation modeling the situation will be of the form:

$n=ab^t$

we take two points from the table for evaluating $a$ and $b$ namely points $(2,860)$ and $(4,1250)$

thus we have

(1). $860=ab^2$

(2). $1250=ab^4$

From equation (1) we solve for $a:$

$a=\frac{860}{b^2}$

and put this value into equation (2)

$1250 =\frac{860}{b^2}b^4$

$b^2=\frac{1250}{860}$

$\boxed{b=1.2056}$

with this value $b$ , we solve for $a$ in equation (1):

$860=a(1.2056)^2$

$a=\frac{860}{(1.2056)^2}$

$\boxed{a=591.68}$

Thus we have the equation

$\boxed{n=591.68(1.2056)^t}$

8 0

3 years ago

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8_murik_8 [283]

48 in2 should be the answer

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