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Dima020 [189]
3 years ago
15

In a calorimetry experiment the water absorbs 273 J of heat (q), how much heat (q) is released by the metal if no heat is lost?

Remember: -qreleased = qabsorbed ANS: _____ kJ/mol
Chemistry
1 answer:
makkiz [27]3 years ago
5 0

Answer:

qreleased = -273J.

Explanation:

Hello there!

In this case, according to this calorimetry question, and keeping in mind that the hot substance releases heat to the cold substance which absorbs it, according to:

-qreleased = qabsorbed

In such a wat, since the water absorbs 273 J of heat and no heat is lost, the amount of this measurement released by the metal is:

-qreleased = 273J  

qreleased = -273J

Regards!

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b) The mole fraction and partial pressure of hydrogen is  0.89 and 1.59 atm respectively

c) The mole fraction and the partial pressure  of argon is 0.11 and 0.19 atm.

<h3>What is the total pressure?</h3>

We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;

PV = nRT

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

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Number of moles of Argon = 36.7 g/40 g/mol

= 0.92 moles

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Learn more about partial pressure:brainly.com/question/13199169

#SPJ1

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