At constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.
<h3>What is Boyle's law?</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given that;
- Initial volume of the gas V₁ = 22.5L
- Initial pressure of the gas P₁ = 0.98atm
- Final pressure of the gas P₂ = 0.95atm
- Final volume of the gas V₂ = ?
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = (0.98atm × 22.5L) / 0.95atm
V₂ = 22.05Latm / 0.95atm
V₂ = 23.2L
Therefore, at constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.
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Answer:
CaCO3(aq) → Ca2+(aq ) + CO3 2-(aq)
Explanation:
- Dissolution reactions are reactions that occur when a solute either in gaseous, liquid, or solid form dissolves in a solvent such as water to form a solution.
- In this case we are given Calcium carbonate (CaCO3) which undergoes dissolution according to the equation;
- CaCO3(aq) → Ca2+(aq ) + CO3 2-(aq)
- Then<em><u> the bicarbonate ion combines with two protons from water to form a weak acid H2CO3. The weak acid is then broken down to form CO2 and H2O since its unstable.</u></em>
Answer:
Liquid A is a homogeneous mixture and Liquid B is a heterogeneous mixture
Explanation:
Answer:
Alkane
Alkene
Alkyne
Explanation:
Alkane=1 bond (Saturated hydrocarbon)
Alkene= 2 bonds (Unsaturated hydrocarbon)
Alkyne= triple bonds (Unsaturated hydrocarbon)
Formula of Alkane = CnH2n+2
Formula of Alkene = CnH2n
Formula of Alkyne = CnH2n-2
Lunch of a patient has 3 oz skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk
Energy content of 3 oz skinless chicken is = 110 kcal
Energy content of 3 oz broccoli = 30 kcal
Energy content of 1 medium apple = 60 kcal
Energy content of 1 cup non-fat milk = 90 kcal
So the kilocalories of energy patient obtained from lunch
= 110 kcal+ 30 kcal + 60 kcal + 90 kcal = 290 kcal
