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algol [13]
3 years ago
9

Write and balance the chemical equation that represents the reaction of aqueous sulfuric acid with aqueous sodium hydroxide to f

orm water and sodium sulfate. Include phases.
Chemistry
1 answer:
NikAS [45]3 years ago
8 0
H2SO4_aq+NaOH_aq => Na2[SO4]_s+2[H2O]
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The Brønsted-Lowry theory defines an acid as a(n)
Novosadov [1.4K]
Letra A. Doador de H+
6 0
4 years ago
25. Which of the following is represented in the highest percentage by volume in dry air? A. Carbon dioxide B. Hydrogen C. Nitro
emmasim [6.3K]
The correct option is C. Nitrogen gas has the highest percentage by volume of all the gases that make up the air.
The composition of the air is as follows:
nitrogen = 78.09%
Oxygen = 20.95%
Argon = 0.93%
Carbon dioxide = 0.04%
water vapour = traces amount.

8 0
4 years ago
Complete this nuclear reaction by selecting which particle would go in the
kompoz [17]

Answer:

Missing particles: ^{0}_{1}e^{+} (a positron) and an electron neutrino \nu_{\rm e}.

The nuclear equation would be:

{\rm ^{19}_{10} Ne} \to ^{0}_{1}e^{+} + {\rm ^{19}_{\phantom{1}9}F }+ \nu_{e}.

Explanation:

The mass number of a particle is the number on the top-right corner of its symbol.

The atomic number of a particle is the number on the lower-right corner of its symbol.

The nuclear reaction here resembles a beta-plus decay. The mass numbers of the two nuclei are equal. However, the atomic number of the product nucleus is lower than that of the reactant nucleus by 1.

A beta decay may either be a beta-plus decay or a beta-minus decay. In a beta-plus decay, a positively-charged positron ^{0}_{1}e^{+} and an electron neutrino \nu_e would be released. On the other hand, in a beta-minus decay, a negatively-charged electron \rm ^{0}_{1}e^{-} and an electron antineutrino \overline{\nu}_e would be released.

Electric charge needs to be conserved in nuclear reactions, including this one.

The atomic number of the \rm Ne nucleus on the left-hand side is 10, meaning that the nucleus has a charge of +10. On the other hand, the atomic number of the \rm F nucleus on the right-hand side shows that this nucleus carries a charge of only +9.

By the conservation of electric charge, the particles on the right-hand side must carry a positive charge of +1. That rules out the possibility of the combination of one negatively-charged electron \rm ^{0}_{1}e^{-} (with a charge of -1) and an electron antineutrino \overline{\nu}_e (with no electric charge at all.)

Hence, the only possibility is that the missing particle is a positron (and an electron neutrino \nu_e, which carries no electric charge.)

4 0
3 years ago
Features passed from parent to offspring, such as eye color, is an example of what?
Olenka [21]
Parents pass characteristics such as hair color, nose shape, and skin color to their offspring. Not all of the parents' characteristics will appear in the offspring, but the characteristics that are more likely to appear can be predicted.
5 0
3 years ago
At a certain temperature a 42.55% (v/v) solution of ethyl alcohol, C2H5OH, in water has a density of 0.9027 g mL-1. The density
swat32

Answer:

a. 7.187M.

b. 7.962m.

c. 0.1846

Explanation:

This solution contains 42.55mL of ethyl alcohol in 100mL of solution.

a. Molar concentration = Moles ethyl alcohol / L solution:

<em>Moles ethyl alcohol -Molar mass: 46.07g/mol-</em>

42.55mL * (0.7782g/mL) * (1mol / 46.07g) = 0.7187 moles ethyl alcohol

<em>Liters solution:</em>

100mL * (1L / 100mL) = 0.100L

Molar concentration: 0.7187mol / 0.100L = 7.187M

b. Molal concentration: Moles ethyl alcohol (0.7187moles) / kg solution

<em>kg solution:</em>

100mL * (0.9027g / mL) * (1kg / 1000g) = 0.09027kg

Molal concentration: 0.7187mol / 0.09027kg = 7.962m

c. Mole fraction: Moles ethyl alcohol / Moles ethyl alcohol + moles water

<em>Moles water: -molar mass: 18.01g/mol-</em>

Volume water = 100mL - 42.55mL = 57.45mL

57.45mL * (0.9949g/mL) * (1mol/18.01g) = 3.1736 moles water

<em>Moles fraction:</em>

0.7187 moles ethyl alcohol / 0.7187 moles ethyl alcohol+3.1736 moles water

= 0.1846

4 0
3 years ago
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