I think it would be option 4?
We use the given masses of the reactants to calculate the moles of Mn and Cl. Empirical formula represents the simplest mole ratio of atoms present in a compound.
Moles of Mn = 
Moles of Cl =
= 0.710 mol Cl
Simplest mole ratio: 
So the empirical formula is 
Answer:
B.) The molecule is a branched hydrocarbon.
Explanation:
A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.
If i had to answer i would choose a hope this helps
Answer:
It is important to analyze data to further understand what's going on. By analyzing data, you know more about what you are investigating. Without analyzing data, you may find it harder to figure something.