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Elan Coil [88]
3 years ago
9

The distance in feet that Karina swims in a race is represented by 6d - 6, where d is the distance for

Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0
The answer would be a hope it helps
You might be interested in
Step 3: 2x > 10 Step 4: x > 5 What property justifies the work between step 3 and step 4? A. division property of inequali
BigorU [14]

Answer:

A. Division property of inequality.

Step-by-step explanation:

Let be 2\cdot x > 10, we proceed to show the appropriate procedure to step 4:

1) 2\cdot x >10 Given

2) x > 5 Compatibility with multiplication/Existence of multiplicative inverse/Associative property/Modulative property/Result. (Division property of inequality)

In consequence, the division property of inequality which states that:

\forall\, a, b, c \in \mathbb{R}. If c > 0, then:

a> b\,\longrightarrow a\cdot c > b\cdot c \,\lor\, a

But if c < 0, then:

a> b\,\longrightarrow a\cdot c < b\cdot c \,\lor\, a b\cdot c

Hence, correct answer is A.

5 0
3 years ago
Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: E
rjkz [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: Equals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?

Jane's evaluation :

x² - 3x + 5 for x = - 2

Step 1:

(-2)² - 3(-2) + 5

Step 2:

-4 + 6 + 5

Step 3 :

= 7

Jane's mistake was in STEP2,

evaluating (-2)² = 4 and not - 4

Hence, (-2)² - 3(-2) + 5

= 4 + 6 + 5

= 15

4 0
2 years ago
Determine if the conditional statement is true or false given the following: p is false. q is false. Is -q -p true or false?
Vikki [24]

Hello,

if p is false then ~p is true

if q is false then ~q is true

if ~p is true and ~q is true then <u>~q and ~p is true</u>

3 0
3 years ago
How do you answer number 5
riadik2000 [5.3K]

x² - x - 6  = (x +3)(x - 2)

x² - 5x + 6 = (x - 2)(x - 3)

What is their common factor?

Answer: B. x - 2

5 0
3 years ago
A violin student records the number of hours she spends practicing during each of nine consecutive weeks: 6.2 5.0 4.3 7.4 5.8 7.
spin [16.1K]

Answer:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

For this case we need to sort the data first on increasing way and we got:

1.2, 4.3, 5.0, 5.8, 6.2, 6.3, 7.2, 7.4, 8.4

For this case we have 9 values the median would be on the 5 position:

Median = 6.2

The first quartile would be 5 since we analyze 1.2, 4.3, 5.0, 5.8, 6.2 and the middle point is 5.0

The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

IQR = Q_3 -Q_1= 7.2-5=2.2

And 1.5 IQR = 1.5*2.2=3.3

The lower limit on this case would be:

LL= Q_1 -1.5 IQR= 5-3.3=1.7

And our value is 1.2 is lower than the lower limit 1.7

Considering the smallest data value (1.2) and using the 1.5 × IQR rule, we would:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below  the first quartile.

False 1.2 is more than 1.5 IQR below the first quartile

C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  median.

False, we analyze if is an outlier comparing with the Q1 or Q3 not with the median

D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

5 0
2 years ago
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