We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).
The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
According to the given question.
We have an equation

So, to find the resulting equation of the above equation we need to simplify.
First we will take LCD



Multiply both the sides by x.

Again multiply both the sides by x



Factorize the above equation
⇒3x(x+6)+2(x+6) = 0
⇒(3x + 2)(x+6) = 0
⇒ x = -2/3 or x = -6
Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
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The answer is B
the steps are these
interchange the x and y variables
x=5y-8
solve for y so we get
y = x+8
----
5
Answer:
1. x= y/5 + 22/5
2. y=17 − 3x2
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
by rewriting the function we can see that it has a minimum at
![y=7x^2+7x-7\Rightarrow y=7(x^2+x-1)\Rightarrow y=7[(x+\frac{1}{2})^2-\frac{1}{4}-1]\Rightarrow](https://tex.z-dn.net/?f=y%3D7x%5E2%2B7x-7%5CRightarrow%20y%3D7%28x%5E2%2Bx-1%29%5CRightarrow%20y%3D7%5B%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2-%5Cfrac%7B1%7D%7B4%7D-1%5D%5CRightarrow)
![y=7[(x+\frac{1}{2})^2-\frac{5}{4}]\Rightarrow minimum \ (-\frac{1}{2}, -\frac{35}{4})](https://tex.z-dn.net/?f=y%3D7%5B%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2-%5Cfrac%7B5%7D%7B4%7D%5D%5CRightarrow%20minimum%20%5C%20%28-%5Cfrac%7B1%7D%7B2%7D%2C%20-%5Cfrac%7B35%7D%7B4%7D%29)
bye.