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maks197457 [2]
3 years ago
5

380% of what is 99? (Round to the nearest whole number)

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

26

Step-by-step explanation:

380% is equal to = x of 99

(remove zero and make 38 into a decimal)

380% will turn into 3.8

x × 3.8 = 99

x = 99/3.8

99 / 3.8 ≈ 26

scoray [572]3 years ago
6 0

Answer:

  • 26

Step-by-step explanation:

<u>Let the number be x</u>

  • 380% of x is 99
  • x*3.8 = 99
  • x = 99/3.8
  • x = 26 rounded to the nearest whole number
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-1+(-5)

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It takes 2 workers 6 days to paint a mansion. How many days would it take 4
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Answer:

2 workers = 6 days

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3 years ago
The heights of adult men in America are normally distributed, with a mean of 69.8 inches and a standard deviation of 2.69 inches
Brilliant_brown [7]

Answer:

a) 1.93

b) 97.32% of men are SHORTER than 6 feet 3 inches

c) 2.71

d) 0.34% of women are TALLER than 5 feet 11 inches

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)?

For man, \mu = 69.8, \sigma = 2.69

A feet has 12 inches, so this is Z when X = 6*12 + 3 = 75. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 69.8}{2.69}

Z = 1.93

b. What percentage of men are SHORTER than 6 feet 3 inches?

Z = 1.93 has a pvalue of 0.9732

97.32% of men are SHORTER than 6 feet 3 inches

c. If a woman is 5 feet 11 inches tall, what is her z-score (to two decimal places)?

For woman, \mu = 64.1, \sigma = 2.55

Here we have X = 5*12 + 11 = 71.

Z = \frac{X - \mu}{\sigma}

Z = \frac{71 - 64.1}{2.55}

Z = 2.71

d. What percentage of women are TALLER than 5 feet 11 inches?

Z = 2.71 has a pvalue of 0.9966

1 - 0.9966 = 0.0034

0.34% of women are TALLER than 5 feet 11 inches

5 0
4 years ago
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