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maks197457 [2]
3 years ago
5

380% of what is 99? (Round to the nearest whole number)

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

26

Step-by-step explanation:

380% is equal to = x of 99

(remove zero and make 38 into a decimal)

380% will turn into 3.8

x × 3.8 = 99

x = 99/3.8

99 / 3.8 ≈ 26

scoray [572]3 years ago
6 0

Answer:

  • 26

Step-by-step explanation:

<u>Let the number be x</u>

  • 380% of x is 99
  • x*3.8 = 99
  • x = 99/3.8
  • x = 26 rounded to the nearest whole number
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Answer:

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Step-by-step explanation:

a - 6 - 6a = 4

a-6a=10

-5a=10

a=10/-5

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Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value. Find that value and explain how you know.
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Answer:

The vertex is the point (-1,11). is a maximum

Step-by-step explanation:

we know that

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f(x)=a(x-h)^{2}+k

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(h,k) is the vertex

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we have

f(x)=-5x^{2}-10x+6

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f(x)-6=-5x^{2}-10x

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Rewrite as perfect squares

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3 years ago
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
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Answer:

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Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

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Therefore ,

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\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

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\rule{200}{4}

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