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xxMikexx [17]
3 years ago
12

The liver and esophagus are part of the digestive system. True or False

Mathematics
2 answers:
levacccp [35]3 years ago
4 0
The answer is True yes liver and esophagus are part of digestive system
nalin [4]3 years ago
3 0
The correct answer would be true
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A recent trend in advertising is viral marketing. The goal is to convince viewers to share an amusing advertisement by e-mail or
77julia77 [94]
I'm not sure what you are looking for but I'll answer this question based on what I think is needed.

Given:
Day 1: 130 
Day 2: 130 x 4 = 520
Day 3: 520 x 4 = 2,080

The exponential equation of this problem is:
V(n) = 130(4)^n

Where n is the number of days since the video was first shown.

Let us assume that 10 days have past. Total view would be:

V(n) = 130(4)^n

V(10) = 130(4)^10
V(10) = 130(1,048,576)
V(10) = 136,314,880

After 10 days, there are more than 136 Million views of the viral video.



5 0
3 years ago
If you calculate sle to be $25,000 and that there will be one occurrence every four years (aro), then what is the ale?
Cloud [144]

If you calculate SLE to be $25,000 and that there will be one occurrence every four years (ARO), then the ALE is $40,000.

<h3>What is Single-loss expectancy (SLE)?</h3>

A expected monetary decline each moment an asset is at risk is referred to as single-loss expectancy (SLE). It is a term that is most frequently used during risk analysis and attempts to assign a monetary value to each individual threat.

Quantitative risk analysis predicts the likelihood of certain risk outcomes as well as their approximate monetary cost using relevant, verifiable data.

IT professionals must consider a wide range of risks, including the following:

  1. Errors caused by humans
  2. Cyber attacks, unauthorised data disclosure, or data misuse are examples of hostile action.
  3. Errors in application
  4. System or network failures
  5. Physical harm caused by fire, natural disasters, or vandalism.

To know more about the Single-loss expectancy (SLE), here

brainly.com/question/14587600

#SPJ4

5 0
1 year ago
In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
Tems11 [23]

Answer:  3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: n(E\cup N=50)

n(E)=46\\\\n(N)=7

For any two event A and B, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)

Similarly , n(E\cup N)=n(E)+n(N)-n(E\cap N)

50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3

Hence, 3 students have piercings both on their ears and their noses.

7 0
3 years ago
The frequency table shows how many visits to the library students in a school have made in the last month.
vfiekz [6]
<h3>Answer:  2.8</h3>

=======================================================

Explanation:

Multiply each visit count with their corresponding frequency.

Examples:

  • 0*12 = 0 for the first row.
  • 1*366 = 366 for the second row
  • 2*53 = 106 for the third row

and so on...

I recommend making a third column like this

\begin{array}{|c|c|c|} \cline{1-3}\text{Visits} & \text{Frequency} & \text{Visits*Frequency}\\\cline{1-3}0 & 12 & 0\\\cline{1-3}1 & 366 & 366\\\cline{1-3}2 & 53 & 106\\\cline{1-3}3 & 52 & 156\\\cline{1-3}4 & 155 & 620\\\cline{1-3}5 & 243 & 1215\\\cline{1-3}\end{array}

That way you can keep track of all the results in an organized way.

Then add everything in the third column

0+366+106+156+620+1215 = 2463

Divide this sum over the total frequency (12+366+53+52+155+243 = 881) and we'll get the mean

2463/881 = 2.7956867

Rounding to one decimal place gets us to 2.8 as the final answer.

-------------

The much longer way to do this is to imagine 12 copies of "0", 366 copies of "1", 53 copies of "2", and so on. We'll have an extremely large data set of 881 items inside it. As you can see, this second method is definitely not recommended to actually carry out. Rather it's helpful to have this as a thought experiment to see why we revert to multiplication instead.

Eg: Imagine adding 155 copies of "4". A shortcut is to simply say 4*155 = 620

4 0
2 years ago
Read 2 more answers
What are the missing values in the following geometric sequence?
dezoksy [38]

Answer: 9;0;-3

Step-by-step explanation:

3 0
3 years ago
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