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Elanso [62]
4 years ago
10

How do you factor the expression 20k+50

Mathematics
2 answers:
vovangra [49]4 years ago
5 0
Find the greates common factor between the two numbers being added which is 10, and divide them. Next put the two quotients in separate parentheses and multiply each one by 10 separatelyas shown:

10(2k) + 10(5)
Aliun [14]4 years ago
4 0
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
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A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
Luis bought stock at $66.80. The next day, the price increased $13.85. This new price changed by −2 3 /4 % the following day. Wh
larisa86 [58]
We know that
1) <span>Luis bought stock at ---------------> $66.80
2) </span><span>The next day, the price increased $13.85--------> $66.80+$13.85=$80.65
3) </span><span>This new price changed by −2 3 /4 % the following day
2 3/4%----> (2*4+3)/4----> 11/4 %----> 2.75%
so
(100%-2.75%)-----> 97.25%
t</span><span>he final stock price is $80.65*0.9725-----> $78.43

the answer is 
</span>$78.43<span>

</span>
6 0
3 years ago
Please help this is for my maths midterm and i have no idea how to solve
slava [35]

Step-by-step explanation:

4 0
3 years ago
What percentage of $25000 is $6000
ollegr [7]
Solution for 600 is what percent of 25000:

600:25000*100 =

(600*100):25000 =

60000:25000 = 2.4

Now we have: 600 is what percent of 25000 = 2.4
4 0
3 years ago
What are the value(s) for K? 7K^3=56 Please show your work
Phoenix [80]
I hope this helps you

6 0
3 years ago
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