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3 years ago

How do you factor the expression 20k+50

2 answers:

5 0

Find the greates common factor between the two numbers being added which is 10, and divide them. Next put the two quotients in separate parentheses and multiply each one by 10 separatelyas shown:

10(2k) + 10(5)

Aliun [14]3 years ago

4 0

Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.

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Brad says that if a second number is 125% of the first number than the second number must be 75% of the second number is he corr

elena-s [515]

Answer:

Incorrect.

Step-by-step explanation:

Let, the first number is x, and the second number is y. Given, the second number is 125% of the first number. So, the equation will be

y = 1.25 x

Or, y= 5/4x

Now, multiplying it with 4/5, we get, x= 4/5y

Or, x= 0.80 y

But, Brad is saying the first number must be 75% of the second number. But here we see that the first number is 80% of the second number. That's why Brad is incorrect.

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2 years ago

Find the area of the figure. If necessary, round to the nearest tenth.

nirvana33 [79]

Answer:9.4cm2

Step-by-step explanation:

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2 years ago

What is the following quotient?<br><br> Square root of 120/square root of 30

Mekhanik [1.2K]

Answer:

The square root of 120 is 10.9545.

The square root of 30 is 5.47723.

10.9545 divided by 5.47723 is approximately 2.0000073

7 0

2 years ago

Find the value of x

kodGreya [7K]

Answer:

Last Option

Step-by-step explanation:

We have a triangle and we know its three sides.

We want to find one of your anguos. Then we use the cosine theorem.

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx$

Where

$c = 14\\a = 11\\b = 19$

Now we solve for x from the equation

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx\\\\\\14^2 = 11^2 + 19^2 -2(11)(19)cosx\\\\14^2 -11^2 -19^2 = 2(11)(19)cosx\\\\-286=2(11)(19)cosx\\\\cosx = \frac{-286}{2(11)(19)}\\\\x = arcos(\frac{-286}{2(11)(19)})\\\\x = 46.8\°$

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago