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3 years ago

Help pls!! Whoever answers gets marked brainliest

Mathematics

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

10. x= 10 y=sqrt 200

11. x=y=450

12. x=19 y=sqrt 1083

13. x=sqrt 48 y=sqrt 12

Step-by-step explanation:

10.

x and 10 are the same

10^2+10^2=200

sqrt 200 is not a whole number so y is just sqrt 200

11.

30^2=2x^2 because x and y are the same

x^2=450

sqrt 450 is not a whole number so x and y are just sqrt 450

12.

x= 38 divided by 2=19

38^2=19^2+y^2

1444=361+y^2

y^2=1083

sqrt 1083 is not a whole number so y is just sqrt 1083

13.

x^2=(x/2)^2+36=x^2/4+36

x^2=48

sqrt 48 is not a whole number so x is just sqrt 48

y is half of x so it is sqrt 12

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4 years ago

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Answer:

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Step-by-step explanation:

We are given the following in the question:

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Defense: 265, 276, 255, 306, 317, 281, 268, 282, 260, 261, 256, 286

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$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{3627}{12} = 302.25$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted Data: 263, 265, 267, 292, 302, 308, 311, 316, 324, 325, 325, 329

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{308+311}{2} = 309.5$

b) mean and median weight for the defensive linemen

$Mean =\displaystyle\frac{3313}{12} = 276.08$

Sorted Data: 255, 256, 260, 261, 265, 268, 276, 281, 282, 286, 306, 317

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{268+276}{2} = 272$

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2 years ago

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