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3 years ago

Help pls!! Whoever answers gets marked brainliest

Mathematics

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

10. x= 10 y=sqrt 200

11. x=y=450

12. x=19 y=sqrt 1083

13. x=sqrt 48 y=sqrt 12

Step-by-step explanation:

10.

x and 10 are the same

10^2+10^2=200

sqrt 200 is not a whole number so y is just sqrt 200

11.

30^2=2x^2 because x and y are the same

x^2=450

sqrt 450 is not a whole number so x and y are just sqrt 450

12.

x= 38 divided by 2=19

38^2=19^2+y^2

1444=361+y^2

y^2=1083

sqrt 1083 is not a whole number so y is just sqrt 1083

13.

x^2=(x/2)^2+36=x^2/4+36

x^2=48

sqrt 48 is not a whole number so x is just sqrt 48

y is half of x so it is sqrt 12

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Isabella has a 22 ounce cola. She drinks 17 ounces. Enter the percentage of ounces Isabella has left of her cola. Round your ans

jenyasd209 [6]

Answer:

22.73% of ounces Isabella has left of her cola.

Step-by-step explanation:

Given:

Isabella has a 22 ounce cola. She drinks 17 ounces.

Now, to find the percentage of ounces Isabella has left of her cola.

Total ounces of cola = 22.

Ounces of cola Isabella drink = 17.

So, the ounces of cola she left:

Total ounces of cola - ounces of cola Isabella drink.

$=22-17$

$=5\ ounces.$

Thus, 5 ounces of cola she left.

Now, to get the percentage of cola she left:

$\frac{5}{22}\times 100$

$=\frac{500}{22}$

$=22.727\%.$

Rounding the percentage to the nearest hundredths is 22.73%.

Therefore, 22.73% of ounces Isabella has left of her cola.

7 0

3 years ago

Pls help! will give brainlist!

algol [13]

Answer:

A. (2,5)

because 3×2 is 6, 6-1 is 5

so y=5

4 0

3 years ago

PLEASE HELP!! MATH FINAL + NO EXPLANATION NEEDED :))

Arturiano [62]

F(x+6) +2 up and right in a graph is positive

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3 years ago

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How do you find the volume of the solid generated by revolving the region bounded by the graphs

d1i1m1o1n [39]

Answer:

About the x axis

$V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

Step-by-step explanation:

For this case we have the following functions:

$y = 2x^2 , y=0, X=2$

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on y from 0 to 8.

We can find the area like this:

$A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= 4\pi \int_{0}^2 x^4 dx$

$V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

For this case we need to find the function in terms of x like this:

$x^2 = \frac{y}{2}$

$x = \pm \sqrt{\frac{y}{2}}$ but on this case we are just interested on the + part $x=\sqrt{\frac{y}{2}}$ as we can see on the second figure attached.

We can find the area like this:

$A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy$

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= \pi \int_{0}^2 64-32x^2 +4x^4 dx$

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \frac{\pi}{2} \int_{0}^8 y dy$

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

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3 years ago

Rose’s grandmother is 89 years old. She can knit mittens somewhere between 13 and 16 hours. If she wants to knit 36 mittens for

kakasveta [241]

If it takes that long to make one pair, then i’d say maybe 468 hours to make all 36 pairs

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2 years ago

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