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3 years ago

Find the t-value such that the area in the right tail is 0.005 with 28 degrees of freedom.

Mathematics

1 answer:

klasskru [66]3 years ago

4 0

Answer:

$t = 3.673900$

Step-by-step explanation:

Given

$df = 28$ -- degree of freedom

$Area = 0.005$

Required

Determine the t-value

The given parameters can be illustrated as follows:

$P(T > t) = \alpha$

Where

$\alpha = 0.005$

So, we have:

$P(T>t) = 0.005$

To solve further, we make use of the attached the student's t distribution table.

From the attached table,

The t-value is given at the row with df = 28 and $\alpha = 0.005$ is 3.673900

Hence, $t = 3.673900$

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I NEED HELP PLSSSSSSSS

AVprozaik [17]

Answer:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

Step-by-step explanation:

From the question given above,

y = 8 × (½)ˣ

When x = –1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¯¹

y = 8 × 2

y = 16

When x = 1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¹

y = 8 × ½

y = 4

When x = 2, y =?

y = 8 × (½)ˣ

y = 8 × (½)²

y = 8 × ¼

y = 2

When x = 3, y =?

y = 8 × (½)ˣ

y = 8 × (½)³

y = 8 × ⅛

y = 1

SUMMARY:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

4 0

2 years ago

B is the midpoint of ac. Ab = x+9 and bc = 3x-7 find x and ac

natali 33 [55]

To solve this problem, we need to know 2 relationships:

The distance of AC is the sum of AB and BC.

$AC = AB + BC$

We know this since the distance of going from A to C (AC) is the same as going from A to B (AB), then B to C (BC).

The distance of AB is the same as AC.

$AB = BC$

We know this since B is in the middle of AC, so the distance from B to A (BA) is the same as the distance from B to C (BC).

You can see the attached image (at the bottom) for a visualization of this.

<h2>Putting them together</h2>

Since we know the values of AB and BC...

$AB = x+9\\BC = 3x-7$

...we can put these values into our 2nd equation and solve for x:

$AB = BC\\x + 9 = 3x -7$

Add 7 to both sides:

$x + 16 = 3x$

Subtract x from both sides:

$16 = 2x$

Divide both sides by 2:

$8 = x\\x = 8$

Knowing x, we can find the distance of AC using our first equation.

$AC = AB + BC$

Let's put in the values of AB and BC:

$AC = (x+9) + (3x-7)$

Before we put in x = 8, we can simplify this:

$AC = (x+9) + (3x-7)\\AC = x + 9 + 3x -7\\AC = x + 3x + 9 -7\\AC = 4x + 9 - 7\\AC = 4x+2$

We group x and 3x and add those together. Then we subtract 7 from 9.

With this equation, we can put in x = 8:

$AC = 4x +2\\AC = 4*8 + 2$

Since 4 * 8 = 32:

$AC = 4 * 8 + 2\\AC = 32 + 2\\AC = 34$

Finally, we have found both x and AC.

<h2>Answer</h2>

x = 8

AC = 34

7 0

3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

<u>Calculus</u>

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

<u>Step 2: Find Right-Side Limit</u>

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

<u>Step 3: Find Left-Side Limit</u>

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

3 years ago

What is the slope of the line shown below?

Ivan

We can use the points (-4, 3) and (3, 1) to solve.

Slope formula: y2-y1/x2-x1

1-3/3-(-4)

-2/7

Therefore, the answer is C

Best of Luck!

6 0

3 years ago

Read 2 more answers

Which construction of parallel lines is justified by the theorem "when two lines are intersected by a transversal and the corres

Ugo [173]

Answer:

Step-by-step explanation:

I think you missed attaching the photo, please see my attachment.

And the correct answer is C,

When you look at where the arc meets the parallel lines, if you create a seam between two points, you get a straight line parallel to the horizontal lines so it makes the corresponding angles are congruent.

5 0

3 years ago