The answer would be A 20c/d
Answer:
r = 6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
PR² = PQ² + QR² , substitute values
(r + 4)² = r² + 8²
r² + 8r + 16 = r² + 64 ( subtract r² from both sides )
8r + 16 = 64 ( subtract 16 from both sides )
8r = 48 ( divide both sides by 8 )
r = 6
Answer:
So basically anything higher than .5 would be x>.5 so it has to be greater than or equal to .51
Step-by-step explanation:
.51 .75 .89 .56 .78 .86 .61 it goes on and on as long as it is greater than .50
Vertex form uses the following formula:

Identify the values of h and k in your function:


The vertex is found with the following point:


The vertex will be found at
(-5, -28).
Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Step-by-step explanation:
<em>Explanation</em>:-
<em>Given sample size 'n' =10</em>
<em>mean of the Population = 90 words per minute</em>
<em>standard deviation of the Population =10 wpm </em>
<em>we will use formula</em>
<em> </em>
<em></em>
<em>Let X⁻ = 96</em>

Z = 1.898
<em>The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute</em>
<em></em>
<em></em>
<em> = 1- P( Z ≤z⁻)</em>
<em> = 1- P(Z<1.898)</em>
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
<u><em>Final answer</em></u>:-
The probability that a random sample of 10 second grade students from
= 0.0359