A high school club has 10 members who are seniors and 8 members who

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

Answer:

The probability that the person will not be a senior

P(E⁻) = 1 - P(E)

= $1- \frac{5}{9} = \frac{4}{9}$

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given A high school club has 10 members who are seniors and 8 members who are juniors

n(S) = 10 + 8 = 18

If a member is randomly selected to be the club president

Let 'E' be the event that the person will be a senior

The probability that the person will be a senior

$P(E) = \frac{n(E)}{n(S)}$

$P(E) = \frac{n(E)}{n(S)} = \frac{10}{18} = \frac{5}{9}$

The probability that the person will not be a senior

P(E⁻) = 1 - P(E)

= $1- \frac{5}{9} = \frac{4}{9}$

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(
3
,
4
)
(
3
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4
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(
−
2
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1
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(
-
2
,
1
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=
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(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
Distance
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(
x
2
-
x
1
)
2
+
(
y
2
-
y
1
)
2
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√
(
(
−
2
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−
3
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2
+
(
1
−
4
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2
(
(
-
2
)
-
3
)
2
+
(
1
-
4
)
2
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34
34
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Exact Form:
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34
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