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3 years ago

Julien threw x number of pitches at baseball practice. Jacob threw 1/5 fewer than that

Mathematics

1 answer:

Naily [24]3 years ago

5 0

Answer:

ok so jacob threw 1/5 of x

Step-by-step explanation:

if you say julien threw x and jacob threw 1/5 of that than jacob threw 1/5 of x

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Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

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2 years ago

Find the missing sides of the given similar triangle

tiny-mole [99]

Provide an attachment so we can assist you.

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3 years ago

If a point is picked at random from the largest rectangle, what is the probability that it is not shaded? Assume that all of the

tia_tia [17]

$|\Omega|=32\\ |A|=14\\\\ P(A)=\dfrac{14}{32}=\dfrac{7}{16}\approx44\%$

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3 years ago

Read 2 more answers

Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe

serg [7]

Answer:

s = 2q + 3

Step-by-step explanation:

A linear function has the form:

● y = mx + b

● y is the output of the function

● x is the variabke that we input

● b is the y-intetcept.

Focus on y and x.

Notice that y depends of the value of x. The value of y changes by changing x. So the value of x controls the output y.

y is dependent but x is not.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● 6q = 3s - 9

We want q to be the independent variable wich means that q will be the input. Therefore s should be the output.

The strategy we are going to follow is separating s in one side alone.

● 6q = 3s - 9

Add 9 to both sides

● 6q + 9 = 3s -9 + 9

● 6q + 9 = 3s

Divide both sides by 3

● (6q + 9)/3 = (3s)/3

● (6q)/3 + 9/3 = s

● s = 2q + 3

So the answer is s = 2q + 3

6 0

3 years ago

Dylan has a 32-ounce coffee.He drinks 4 ounces. What is the percentage of ounces left of his coffee?

Semenov [28]

$32 \div 100 = 3.125 \\ \\ 3.125 \times 4 = 12.5 \\ \\ 100 - 12.5 = 87.5 \\ \\ 87.5$

8 0

3 years ago