If x=6 and y=2 then the value of 3x^2-4(2y-4/12) +8
1 answer:
Answer:
3x^2−8y+28/3
Step-by-step explanation:
3x^2-4(2y-4/12) +8
Reduce the fraction 4/12 to lowest terms by extracting and canceling out 4.
3x^2-4(2y-1/3) +8
Use the distributive property to multiply −4 by 2y - 1/3
3x^2-8y+4/3+8
Add 4/3 and 8 to get 28/3
3x^2−8y+28/3
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