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beks73 [17]
3 years ago
14

What is 91,360 in expanded form​

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

Expanded Notation Form:

 91,360 =

 90,000  

+ 1,000  

+ 300  

+ 60  

+ 0  

Expanded Factors Form:

   91,360 =

 9 × 10,000  

+ 1 × 1,000  

+ 3 × 100  

+ 6 × 10  

+ 0 × 1  

Expanded Exponential Form:

 91,360 =

9 × 104

+ 1 × 103

+ 3 × 102

+ 6 × 101

+ 0 × 100

Word Form:

91,360 =

ninety-one thousand three hundred sixty

Hope this helps! mark me as brainliest if possible, you dont have too!

Step-by-step explanation:

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3 years ago
cory bought 4 apples and 6 oranges and paid 5.10. Dalia bought 2 apples and 5 oranges and paid 3.65. what is the cost of 2 orang
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Step-by-step explanation:

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3 years ago
Solve the system of linear equations by substituting. Check your solution
Ghella [55]
QUESTION 4

The given system of linear equations are,

y = 5x - 7...(1)

and

- 3x - 2y = - 12...(2)

We put equation (1) into equation (2) to obtain,

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We expand to get,

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Group like terms to get,

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Simplify to get,

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Divide both sides by -13 to get,

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y = 5(2) - 7

y = 10 - 7 = 3

The solution is

x = 2 \: \: and \: \: = 3

QUESTION 5

The given system of linear equations are

-4x+y=6....(1)
and

-5x-y=21...(2)

We make y the subject in equation (1) to get,

y = 4x + 6....(3)

Put equation (3) into equation (2) to get,

- 5x - (4x + 6) = 21

We expand to get,

- 5x - 4x - 6 =21

We group like terms to get,

- 5x - 4x = 21 + 6

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x = - 3

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y = 4( - 3) + 6

y = - 12 + 6 = - 6

Therefore the solution is

x = - 3 \: and \: y = - 6

QUESTION 6

The given equations are,

-7x-2y=-13...(1)

and

x-2y=-13...(2)

Make x the subject in equation (2) to get,

x = 2y - 13...(3)

Put equation (3) into equation (1) to get,
- 7(2y - 13) - 2y = - 13

We expand to get,

- 14y + 91 - 2y = - 13

We group like terms to obtain,

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Divide through by -16 to get,

y = \frac{13}{2}

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x = 2( \frac{13}{2} ) - 13

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Therefore

x = 0 \: and \: y = \frac{13}{2}
8 0
3 years ago
the scale of a model railroad set is 3.5 millimeters to one foot if the length of a model car in the set is 150 millimeters what
Montano1993 [528]

\bf \begin{array}{ccll} \stackrel{mm}{model}&\stackrel{ft}{actual}\\ \cline{1-2} 3.5&1\\ 150&x \end{array}\implies \cfrac{3.5}{150}=\cfrac{1}{x}\implies x=\cfrac{150\cdot 1}{3.5}\implies x\approx 42.86

6 0
3 years ago
Read 2 more answers
PLEASE HELP DUE IN AN HOUR NO LINKS PLEASE. ​
Korolek [52]

Answer:

y = 3/2  when x = 15

Step-by-step explanation:

y = k / √1+x  

2 = k / √1+8 = k/3  

k = 6  

y' = 6 / √1+15 = 6/4 = 3/2

5 0
3 years ago
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