All categories

3 years ago

If someone can do all of these for me Ill give brainliest i don’t get it at all.

Mathematics

1 answer:

MArishka [77]3 years ago

7 0

I will not be able to explain but you can surely trust those answers
A = 130
B = 50
C = 50
D = 130
E = 75
F = 105
G = 105
H = 75
I = 40
J = 140
K = 38
L = 102
M = 38
N = 50
O = 95
P = 35
Q = 130
R = 100
S = 100
T = 80
U = 80
V = 35
W = 45
X = 40
Y = 40
Z = 60

You might be interested in

On a team, 8 girls and 7 boys scored a total of 128 points. The difference between the number of points scored by the eight girl

andriy [413]

Answer:

Step-by-step explanation:

128-16=112

112÷15(boys+girls)=7.4666666

7.4666666 rounds to 8

7 0

2 years ago

Read 2 more answers

A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand

beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0

3 years ago

Why are these two angles congruent?

Stella [2.4K]

What angels? You need to show a picture :)

8 0

3 years ago

Read 2 more answers

What is the value of |-7| - |3|

Rudik [331]

Answer:

4 is the correct answer

Step-by-step explanation:

|-7| = 7

|3| = 3

7 - 3 = 4

3 0

2 years ago

The measurement of the height of 600 students of a college is normally distributed with a mean of

ioda

Answer:

Step-by-step explanation:

We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.

We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.

This can be expressed as;

P(170<X<180)

This can be evaluated in Stat-Crunch using the following steps;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 175 and that of the standard deviation as 5

Then input the values 170 and 180

click compute

Stat-Crunch returns a probability of approximately 68%

5 0

3 years ago