Answer:
Option 2, Half of the active sites are occupied by substrate
Explanation:
Michaelis-Menten expression for enzyme catalysed equation is as follows:
![V_0=\frac{V_{max\ [S]}}{k_M+[S]}](https://tex.z-dn.net/?f=V_0%3D%5Cfrac%7BV_%7Bmax%5C%20%5BS%5D%7D%7D%7Bk_M%2B%5BS%5D%7D)
Here,
is Michaelis-Menten constant and [S] is substrate concentration.
When [S]=Km
Rearrange the above equation as follows:
![V_0=\frac{V_{max}[S]}{k_M+[S]}\\V_0=\frac{V_{max}[S]}{[S]+[S]}\\V_0=\frac{V_{max}[S]}{2[S\\]}\\V_0=\frac{V_{max}}{2}](https://tex.z-dn.net/?f=V_0%3D%5Cfrac%7BV_%7Bmax%7D%5BS%5D%7D%7Bk_M%2B%5BS%5D%7D%5C%5CV_0%3D%5Cfrac%7BV_%7Bmax%7D%5BS%5D%7D%7B%5BS%5D%2B%5BS%5D%7D%5C%5CV_0%3D%5Cfrac%7BV_%7Bmax%7D%5BS%5D%7D%7B2%5BS%5C%5C%5D%7D%5C%5CV_0%3D%5Cfrac%7BV_%7Bmax%7D%7D%7B2%7D)
when [S]=Km, the rate of enzyme catalysed reaction becomes half of the maximum rate, that means half of the active sites are occupied by substrate.
Therefore, the correct option is option 2.
<span>electronegativity difference and the 3D arrangement of atoms in the compund.</span>
Answer:
λ = 2.9 × 10⁻⁵ m
General Formulas and Concepts:
c = λν
- C = Speed of Light (3 × 10⁸ m/s)
- ν = frequency (Hz or 1/s⁻¹)
Explanation:
<u>Step 1: Define</u>
ν = 10.4 × 10¹² Hz
<u>Step 2: Solve for λ</u>
- Substitute: 3.0 × 10⁸ = λ(10.4 × 10¹² Hz)
- Divide both sides by ν: 0.000029 = λ
- Rewrite: λ = 2.9 × 10⁻⁵ m
<u>Step 3: Check</u>
<em>We are given 3 sig figs.</em>
Wavelength has only 2 sig figs.
Answer: Go online and you should find if that don't work break the question apart only past some of it
Explanation:
Answer:
G, but I think that theres more than one answer