Answer:Solution A has 10 times more hydrogen ions than solution B.
The correct answer is base
The point of Condensation
Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol
Answer:
0.23 g
Explanation:
From the question given above, the following data were obtained:
Mass of solution = 20.3 g
Percentage by mass of KCl = 1.14%
Mass of KCl =?
The mass of KCl in the solution can be obtained as follow:
Percentage by mass = mass of solute / mass of solution × 100
1.14% = mass of KCl / 20.3
Cross multiply
Mass of KCl = 1.14% × 20.3
Mass of KCl = 1.14/100 × 20.3
Mass of KCl = 0.0114 × 20.3
Mass of KCl = 0.23 g
Therefore, the mass of KCl in the solution is 0.23 g
