We'll use the notation
for the principal value and
for all the values:

Part I


Part II. In our range we can write


Part III.

Part IV.


Answer:
<em>615.44m²</em>
Step-by-step explanation:
The base of the silo is a circle
Rea of the base of the silo = πr²
r is the radius of the silo
Given
radius r = 14m
Area of the base of the silo = π(14)²
Area of the base of the silo = 3.14(196)
Area of the base of the silo = 615.44
<em>Hence the area of the base of the silo is 615.44m²</em>
Answer:b
Step-by-step explanation:
Answer:
the sum is 5
Step-by-step explanation: