Can someone help me solve this please I don’t know how to do it

Mathematics

1 answer:

diamong [38]2 years ago

5 0

Step-by-step explanation:

NO = TS

20 = 3x-7
20+7 = 3x
27 = 3x
27/3 = x
9 = x

Hope this helps you.

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Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer

Firlakuza [10]

Answer: ŷ = 0.07X + 5.2

Step-by-step explanation:

Given the following :

Number of citations 5 - 7.5 - 10 - 15 - 20

Outputs Residuals 3 - - 6 - - 10 - 5 - - 6

Using the online regression calculator :

Line of best fit is represented by the equation:

ŷ = 0.06897X + 5.2069

ŷ = 0.07X + 5.2

From the line equation:

y = mx + c

With 0.07 = slope of gradient(m)

Intercept (c) = 5.2 (point where the line of best fit intersect the y_axis

x and y are values of x and y respectively

8 0

3 years ago

Three numbers X, Y, and Z are in the ratio 2:7:8. If 12 is subtracted from Y, then three numbers form a geometric sequence (in t

Dimas [21]

A geometric sequence is a sequence in which there is a common ratio between any two consecutive terms. In this case if X:Y:Z are in the ratio of 2:7:8 the multiplying by a constant k, we have X=2k, Y= 7k and Z=8k.
Then if X, Y-12, Z form a Geometric sequence, it means X/Y-12=Y-12/Z which is the same as 2k/7k-12=7k-12/8k if we cross multply, we get
16k²= 49k²-168k +144
33k²-168k+144 =0 solving for k
k = 4 or 1.091 if we take the whole number to find the values of X,Y and z,
X= 8, Y= 28 and Z=32

3 0

3 years ago

How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used

MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the n-th term of the sequence, a (n), is given recursively by

• a (1) = 1

• a (n) = a (n - 1) + 21 … … … for n > 1

We can find the explicit rule for the sequence by iterative substitution:

a (2) = a (1) + 21

a (3) = a (2) + 21 = (a (1) + 21) + 21 = a (1) + 2×21

a (4) = a (3) + 21 = (a (1) + 2×21) + 21 = a (1) + 3×21

and so on, with the general pattern

a (n) = a (1) + 21 (n - 1) = 21n - 20

Now, we're told that the sum of some number N of terms in this sequence is 2332. In other words, the N-th partial sum of the sequence is

a (1) + a (2) + a (3) + … + a (N - 1) + a (N) = 2332

or more compactly,

$\displaystyle\sum_{n=1}^N a(n) = 2332$