Answer: The correct option is 5.7/20 = x/200
Step-by-step explanation: Please refer to the diagram attached for more details.
From the 7-column by 2-row table drawn, you can determine that the mean number of catfish as given in the question is derived as follows;
Mean = Summation of observed data / Number of observations
Mean = (3 + 5 + 7 + 5 + 6 + 8)/6
Mean = 34/6
Mean = 5.6667
Mean ≈ 5.7
Also the mean number of all fish is derived as follows;
Mean = Summation of observed data / Number of observations
Mean = (20 + 20 + 20 + 20 + 20 + 20)/6
Mean = 120/6
Mean = 20
Using relative frequency, we can confidently predict the number of catfish population in the pond. This simply means, if the mean number of catfish is 5.7 and the mean number of all fish is 20, then the relative frequency would be 5.7 over 20 of the total fish population.
Hence, if there is a total of 200 fish in the pond then to predict the proportion which would be catfish can be expressed as follows;
StartFraction 5.7 over 20 EndFraction = StartFraction x over 200 EndFraction.
OR better expressed as;
5.7/20 = x/200
The answer is false, they are parallel not perpendicular
Answer:
a) 0.251
b) 0.483
c) 0.0994
Step-by-step explanation:
We are given the following information:
We treat adult adults trusting national newspapers to present the news fairly and accurately as a success.
P(Adult trust) = 60% = 0.6
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 9
a) exactly five
b) at least six
We have to evaluate

c) less than four
We have to evaluate

Answer:
w = -7z/2
Step-by-step explanation:
Our goal is to isolate w
1. subtract 3w from both sides to get 2w+9z = 2z
2. Subtract 9z from both sides to get 2w = -7z
3. Divide both sides by 2 to get w = -7z/2
We cannot simplify further, so this is our answer.
Answer:
hi again,
Step-by-step explanation:
explanation in the pics!