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jok3333 [9.3K]
3 years ago
8

Question 5(Multiple Choice Worth 3 points) (06.04) Evaluate the expression 7x2y, when x = 5 and y = 3. 210 315 525 728

Mathematics
2 answers:
Natali [406]3 years ago
7 0
Plug in values. 
7x2y = 
7(5)2(3) = 
210 <---------------------Answer
Anastaziya [24]3 years ago
7 0
I typed in 210 it was wrong I think it was 315.
You might be interested in
To solve you must subtract 25 from both
ahrayia [7]

Answer:

What are you subtracting 25 from?

7 0
2 years ago
Simplify 7d+12-14d-3
Alchen [17]
7d+12-14d-3
Combine like terms
-7d+9
Hope this helped. 
4 0
3 years ago
Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product
gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

Step-by-step explanation:

The cost for the four cylinder production line is  C_4 =  \$2,100

The cost for the six cylinder production line is  C_6 = \$3,500

The manufacturing cost for each four cylinder is  M_4= \$13

 The manufacturing cost for each six cylinder is M_6= \$16

  The weekly production capacity for 4 cylinder connecting rod is W_4 = 5,000

   The weekly production capacity for 6 cylinder connecting rod is W_6 = 8,000

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

3 0
3 years ago
Complete the recursive formula of the arithmetic sequence 20, 26, 32, 38, ....
svp [43]

Step-by-step explanation:

a(n) = a +(n-1)d

a=20

d=26-20=6

°.° a(n) = 20 +(n–1)6

a(1) = 20 +(1–1)6=20

hope this helps

6 0
2 years ago
0.64 as a fraction in lowest term<br><br> 1. 64/10<br><br> 2 5/32<br><br> 3. 16/25 <br><br> 4 .4/5
Zepler [3.9K]

Answer:

16/25

Step-by-step explanation:

0.64 = 64/100

64/100 = 16/25

i divided by 4

64/4 = 16

100/4 = 25

4 0
3 years ago
Read 2 more answers
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