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Mathematics

2 answers:

irga5000 [103]3 years ago

7 0

Im pretty sure you put the wrong picture. The slope isn't negative and there is no point O,A, or B.

Veseljchak [2.6K]3 years ago

4 0

Where is O, A and B?

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Write the function a a product of linear factor by grouping or using the x method or a combination of both

Sladkaya [172]

<h3><u>Answer:</u></h3>

$\boxed{\boxed{\pink{\sf Option \ A \ is \ correct .}}}$

<h3><u>Step-by-step explanation:</u></h3>

Given function to us is :-

$\bf \implies g(x) = x^2 - 9$

And we , need to write the function a a product of linear factor by grouping or using the x method or a combination of both . So let's factorise this ,

$\bf \implies g(x) = x^2 - 9 \\\\\bf\implies g(x) = x^2-3^2\\\\\bf\implies \boxed{\red{\bf g(x) = (x+3)(x-3) }}\:\:\bigg\lgroup \blue{\tt Using \ (a+b)(a-b) \ = a^2-b^2 }\bigg\rgroup$

I have also attached the graph of x²-9.

<h3><u>Hence </u><u>option</u><u> </u><u>A</u><u> </u><u>is</u><u> </u><u>corr</u><u>ect</u><u> </u><u>.</u></h3>

4 0

3 years ago

Please help asap i will mark branlist

Rainbow [258]

Answer:

The answer is B

Step-by-step explanation:

7 0

4 years ago

Can someone give me the right answer for this please? I'm so confused

photoshop1234 [79]

Answer:

JK = 18

Step-by-step explanation:

LK = x - 1

KJ = x + 11

LJ = LK + KJ = x - 1 + x + 11

-> LJ = 2x + 10

LM = 12

By tangent secant segment theorem:

$LK \times LJ = JM^2 \\ \\ \implies \: (x - 1)(2x + 10) = {(12)}^{2} \\ \\ \implies \: x (2x + 10) - 1(2x + 10) = 144\\ \\ \implies \: 2x^{2} + 10x - 2x - 10 - 144 = 0\\ \\ \implies \: 2x^{2} + 8x - 154 = 0\\ \\ \implies \: 2(x^{2} + 4x - 77) = 0\\ \\ \implies \: x^{2} + 4x - 77 = 0\\ \\ \implies \: x^{2} + 11x - 7x- 77 = 0\\ \\ \implies \: x(x + 11) - 7(x + 11) = 0\\ \\ \implies \: (x + 11) (x - 7) = 0 \\ \\ \implies \: (x + 11) = 0 \: \: or \: \: (x - 7) = 0 \\ \\ \implies \: x = - 11 \: \: or \: \: x = 7 \\ \\ x \: can \: not \: be \: negative \\ \implies \: x \neq \: - 11 \\ \\ \implies \: x = 7 \\ \\ \implies \: JK = x + 11 = 7 + 11 \\ \\ \implies \: \huge \: { \orange{JK =18}}$