Answer: The constant of variation value of 7.
Step-by-step explanation: We are given cost of 0.8 meter of a silk ribbon = $5.60.
Let us assume y be the total cost for x meter of a silk ribbon and k is the constant of variation.
So, we can set up an equation for proportion relationship:
y = k x.
<em>Let us plug x=0.8 and y= 5.60,</em> in above proportion relationship equation, we get
5.60 = k (0.8).
Dividing both sides by 0.8, we get
5.60/0.8 = k(0.8)/0.8
k =7.
Therefore, the constant of variation value of 7.
Answer:
B. 21
Step-by-step explanation:
The fractions are there to just make the problem seem complicated, but just rewrite it without the fractions.
"What is a common multiple for 7 and 3?"
In this problem it's easy, all you have to do is guess and check.
A: A doesn't work. 7 is not a factor of 18.
B: B works! Both 3 and 7 are factors of 21.
C: C doesn't work. 7 is not a factor of 3.
D: D doesn't work. Neither are a factor of 4.
They only leave us with one solution, B.
First lets distribute the 5x
5x^2 + 30x = -50
Lets divide every term by 5
x^2 + 6x = -10
To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9
Add that to both sides of the equation
x^2 + 6x + 9 = -1
Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)
(x+3)^2 = -1
Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i
For the limit approaching 3 from the right, you want to follow the line to the right of x = 3. From the graph you're describing it sounds like that's y = -3.
The RHS limit is -3 even though f(3) = 7
