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3 years ago

Write 560% as a decimal and as a mixed number

1 answer:

8 0

560% as a decimal = 5.6
(move the decimal points 2 spaces to the left.)

560% as a mixed number = 5 3/5
(divide 560 by 100; 100 goes into 560 5 times so 5 will be your whole number and since you have 60 left you divide 60 by 100; 60/100 can be reduced to 3/5 if you divide the numerator and the denominator by 20)

hope this helps :)

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What is the true solution to ln 20+ln 5= 2 ln x

Aleks [24]

Ln20+ln5=2lnx
ln(20x5)=lnx^2
ln100=1nx^2
100=x^2
square root
x=10

5 0

2 years ago

Read 2 more answers

In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank

fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) $Amount \ of \, water \ remaining \ in \, the \ tank \ is \ \frac{x^3(6-\pi) }{6}$

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The volume of the sphere = $\frac{4}{3} \pi r^3$

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = $\frac{4}{3} \pi \frac{x^3}{8}$ = $\frac{1}{6} \pi x^3$

For tank B

Volume of tank = x³

The volume of the spheres = $8 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = $8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}$

For tank C

Volume of tank = x³

The volume of the spheres = $64 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = $64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}$

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The volume of the spheres = $512 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = $512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}$

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = $x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}$

$Amount \ of \ water \, remaining \, in \, the \ tank = \frac{x^3(6-\pi) }{6}$ .

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3 years ago

Danielle sells

Xelga [282]

Hello! So a 9% commission is earned on the amount of beauty supplies sold. To find out the amount of commission earned, all you have to do is multiply $895 by 9%. 895 * 9% (0.09) is 80.55. $80.55 is earned in commission, Now, add 450 to that amount. 80.55 + 450 is 530.55. There. Danielle earned a total of $530.55 this week.

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2 years ago

а Ava and her children went into a movie theater and she bought $48 worth of drinks and candies. Each drink costs $4 and each ca

adoni [48]

Answer:

x = 6

y = 8

Explanation and graph is given in picture

I hope it helps.