C=2 times j
c=2j
o=j-6
c+j+o=58
subsitte j-6 for o and 2j for c
2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16
sub back
c=2j
c=2(16)
c=32
o=j-6
o=16-6
o=10
curtis=32
olivia=10
jonathan=16
equations are
c+j+o=58
c=2j
o=j-6
Answer:
A. The median weight for shelter A is greater than that for shelter B.
D. The data for shelter B are a symmetric data set.
E. The interquartile range of shelter A is greater than the interquartile range of shelter B.
Step-by-step explanation:
ty for the ptsss
Answer:
fijkhyfvkjyfkjhvkjyufrtgj
Step-by-step explanation
jliuhyfvkjuyfghvkj,hfgjhvkm,jhf
Answer:
15 units squared
Step-by-step explanation:
Area of a trapezium is half the sum of the parallel sides times the distance between them
So A=0.5×(7+3)×3
A=15
