<u>Solution</u><u>:</u><u>-</u>
Let's find roots of x² - 3x + 2
=> x² - 3x + 2 = 0.
=> x² - x - 2x + 2 = 0.
=> x ( x - 1 ) -2 ( x - 1) = 0.
=> ( x - 1 ) ( x - 2 ) = 0.
=> x = 2, 1.
Now
- ( a + ß )² = (2+1)²=3²=9
- ( a - ß )² = ( 2 - 1 )² = 1² = 1.
So , equⁿ would be ,
=> x² - ( 9 + 1)x + 9×1=0.
<u>=> x² - 10x + 9=0.</u>
3/86 I believe because; 1/2 x 3/43 = 1x3 and 2x43 as denominator = 3/86 MULTIPLY both numerators and denominators.
First, we need to get rid of the denominator. to do so, we will simply multiply all terms by 12 (which is the result of 3*4).
(3x/4)(12)+(2/3)(12)=(x/3)(12)
9x + 8 = 4x
then we will separate the variable in one side and solve to get its value
9x-4x = -8
5x = -8
x = -8/5
Answer:
y=3/4x-4
Step-by-step explanation:
The form is y=mx+b so isolate y
-4y=16-3x
y=-16/4-3x/-4
y=3/4x-4
