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kotykmax [81]
3 years ago
13

I need help with this question pls​

Mathematics
2 answers:
MariettaO [177]3 years ago
7 0
C should be the answer.
olga nikolaevna [1]3 years ago
4 0

Answer:

it C

Step-by-step explanation:

just think about it

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1 MORE
gavmur [86]

Answer:

Bai!

Step-by-step explanation:

Thanks for the 50 points!

Stay safe and have a wonderful day/night!! :)

Brainliest?!?!

6 0
3 years ago
I need help <br> Simplify. (x³)⁵
pshichka [43]
The answer would be X^15
7 0
3 years ago
you roll a 6 sided die with faces numbered 1 through 6 and toss a coin what is the probability of rolling a 3 or getting heads
Licemer1 [7]
Rolling a 3 is 1/6
getting heads is 1/2

1/6 * 1/2 = 1/12 (odds of doing both)
5 0
3 years ago
Read 2 more answers
Given that 2x^2 - 2y^2 = 40 and x-y=5, find the value of (x+y)
kipiarov [429]

Answer:

<em>x+y=4</em>

Step-by-step explanation:

hello :

note :  by identity  you have   x²-y² = (x-y)(x+y)

in this exercice : 2x²-2y² = 2(x²-y²) = 2 (x-y)(x+y)

means :   2 (x-y)(x+y) = 40

but x-y = 5

so : 2(5)(x+y) =40

x+y=40/10

<em>x+y=4</em>

5 0
2 years ago
Please help, Thanks for ur help let me know if you need help
KengaRu [80]

Answer:

(3u + 24) / (u + 9)

Step-by-step explanation:

6u + 72 / 2u + 24 ÷ u² + 21u + 108 / u² + 20u + 96

We'll begin by factorising u² + 21u + 108 and u² + 20u + 96. This can be obtained as follow:

u² + 21u + 108

Multiply u² and 108. The result is 108u². Find the factors of 108u² such that their sum will result to 21u. The factors are 12u and 9u.

u² + 12u + 9u + 108

u(u + 12) + 9(u + 12)

(u + 9)(u + 12)

u² + 20u + 96

Multiply u² and 96. The result is 96u². Find the factors of 96u² such that their sum will result to 20u. The factors are 12u and 8u.

u² + 12u + 8u + 96

u(u + 12) + 8(u + 12)

(u + 8)(u + 12)

6u + 72 / 2u + 24 ÷ u² + 21u + 108 / u² + 20u + 96 =

6u + 72 / 2u + 24 ÷ (u + 9)(u + 12) / (u + 8)(u + 12) =

(6u + 72) / (2u + 24) × (u + 8)(u + 12) / (u + 9)(u + 12)

(6u + 72)(u + 8)(u + 12) / (2u + 24)(u + 9)(u + 12) =

(6u + 72)(u + 8) / (2u + 24)(u + 9) =

6(u + 12)(u + 8) / 2(u + 12)(u + 9) =

6(u + 8) / 2(u + 9) = 3(u + 8) / (u + 9)

= (3u + 24) / (u + 9)

8 0
3 years ago
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